Expand the following:
(5 a + b/5)^2
(5 a + b/5) (5 a + b/5) = (5 a) (5 a) + (5 a) (b/5) + (b/5) (5 a) + (b/5) (b/5):
5×5 a a + (5 a b)/5 + (5 b a)/5 + (b b)/(5×5)
(5 a b)/5 = 5/5×a b = a b:
5×5 a a + a b + (5 b a)/5 + (b b)/(5×5)
(b×5 a)/5 = 5/5×b a = b a:
5×5 a a + a b + b a + (b b)/(5×5)
Combine powers. (b b)/(5×5) = (b^(1 + 1))/(5×5):
5×5 a a + a b + b a + (b^(1 + 1))/(5×5)
1 + 1 = 2:
5×5 a a + a b + b a + (b^2/5)/5
5 a×5 a = 5×5 a^2:
5×5 a^2 + a b + b a + (b^2/5)/5
5×5 = 25:
Answer: 25 a^2 + a b + b a + (b^2/5)/5
Rate of change between 1 and 3: find the y values for 1 and 3:
Rate of change = (6-1) / (3-1) = 5/2
Rate of change from 2 and 4:
= (10-3) / (4-2) = 7/2
The rate from 2 to 4 is larger because 7/2 is larger than 5/2
Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:
1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared
The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.
Area = b x h
= 20 x 16
= 320 in. squared
Now all we have left to do is add the two areas to obtain the total area.
Total Area = 320 + 80 = 400 in. squared
<h2>
Answer:</h2>
is 3 ohms
<h2>
Step-by-step explanation:</h2>
In a circuit containing two resistors 
and connected together in parallel, the total resistance 
is given by;
---------(i)
<em>Make </em><em> subject of the formula;</em>
=> 
=> 
=> 
---------------(ii)
From the question,
= 6Ω
= 2Ω
Substitute these values into equation (ii) as follows;
=> 
= 3Ω
Therefore, the value of = 3 ohms or = 3Ω
For this case we propose a system of equations. We have to:
x: Let the variable that represents the number of dimes
y: Let the variable that represents the number of quaters
We know that:
One dime equals 10 cents, $0.10
A quater equals 0.25 cents, $0.25
According to the statement we have:
We multiply the first equation by -0.10:
We have the following equivalent system:
We add the equations:
Approximately 3 quater coins
And two dimes
Answer:
3 quater
2 dimes
