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sergij07 [2.7K]
3 years ago
15

If you have to pay $29.00 per month for a membership, but get 20% off when you pay upfront. How much would you have to pay each

month with the discount?
Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0
You would have to pay $23.2/month

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A cylindrical juice container has the dimensions shown below.
Savatey [412]

Answer:

C is the answer

Step-by-step explanation:

First find the area of the circle -

Use pi times r^2

Since the answers are in pi form, we just need to do the "r^2" part. 3 is the radius, so 3 x 3 = 9. Now that we have found the area of the circle, we will need to multiply the area of the circle by the height of the cylinder. (9pi)(9) = 81pi cubic units. 81pi cubic units is the answer.

8 0
3 years ago
Please choose the correct answers !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
vladimir2022 [97]
The answer is A, C ,B
5 0
3 years ago
A student rolls a number cube whose six faces are numbered 1 through 6.
zalisa [80]

Answer:

B

Step-by-step explanation:

The <u>sample space</u> for this experiment is the set of all possible outcomes.

A student rolls a number cube whose six faces are numbered 1 through 6.

Therefore, all possible outcomes are:

  • rolled number 1;
  • rolled number 2;
  • rolled number 3;
  • rolled number 4;
  • rolled number 5;
  • rolled number 6.

Hence, the sample space is {1, 2, 3, 4, 5, 6}

8 0
3 years ago
Read 2 more answers
What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
Mr. Johns has up to 100 ceramic goods including mugs and plates available for his art class to decorate at the end of the year.
MA_775_DIABLO [31]

Answer:

m + p >= 100

m >= 40

p >= 10

Step-by-step explanation:

let m = number of mugs

let p = number of plates

4 0
3 years ago
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