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4 years ago

6

I need help with this question. "Complete the function table for the given domain, and plot the points on the graph f(x)=-x^2+2x

+5

1 answer:

Anna71 [15]4 years ago

4 0

Answer:

Step-by-step explanation:

i just did this problem wrong and it showed me the correct answer

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1.Jenny and Nola are comaring their phones. The height of Jenny's phone is 4.25 inches, and the height of Nola's phone is 4.75 i

son4ous [18]

I do not know what to answer here can you repost this question and make it a little bit more clear as i am sure it is really confusing to everybody else as it stands right now<span />

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3 years ago

A hospital needs a circular landing pad for their helicopter. The landing pad should be 5000 square feet. The contractor calcula

Fantom [35]

We know that
area of a circle=pi*r²-------> r=√[area/pi]
for area=5000 ft²
r=√[5000/pi]----> r=39.90 ft
39.90*2-----> 79.8 ft of diameter
79.8 ft is > 40 ft

therefore
the answer is
<span>No, he forgot to multiply the radius by 2.</span>

7 0

3 years ago

What is the relationship between the lines with the following equations? 6x+4y=−12 y=−3/2x−5 The lines are perpendicular. The li

andriy [413]

Answer:

I think the answer is "The lines are parallel."

Step-by-step explanation:

3 0

3 years ago

Is 5 + 3(1 - x) equivalent to 8 - 8x?

Readme [11.4K]

Answer:

No, 5 + 3(1 - x) is NOT equivalent to 8 - 8x.

Step-by-step explanation:

To see if they are equivalent to each other, we first need to simplify the first expression:

5 + 3(1 - x)

Distribute the 3 into the parenthesis:

5 + 3 -3x

Combine like terms:

8 - 3x

No, 5 + 3(1 - x) is NOT equivalent to 8 - 8x.

6 0

3 years ago

A test of significance was performed using α=5% . The P‑value was 4% and the power was 85% . What is the probability of a Type I

Ostrovityanka [42]

Answer:

0.15 is the probability of a Type II error for this test.

Step-by-step explanation:

We are given the following information in the question:

Alpha, α = 0.05 = 5%

P‑value = 4% = 0.04

Power of test = 85% = 0.85

We have to find the probability of a Type II error for this test.

The type II error is the error that occurs when we fails to reject a null hypothesis when it is false.

It is a false positive.

It is represented by β.

The relation between power of a test and type II error is given as:

$\text{Power = 1 - Type II error}$

Putting values, we get,

$0.85 = 1-P(\text{Type II error})\\P(\text{Type II error}) = 1-0.85 = 0.15$

0.15 is the probability of a Type II error for this test.

3 0

4 years ago