Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

Answer:

160 not 16

Step-by-step explanation:

Novay_Z [31]2 years ago

4 0

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

$z^{2}=\frac{Ak}{Aj}$

we have

$z=4$

substitute

$4^{2}=\frac{Ak}{Aj}$

$16=\frac{Ak}{Aj}$

$Ak=16Aj$

therefore

The area of triangle K is 16 times greater than the area of triangle J

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Step-by-step explanation:

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