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3 years ago

Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it

Mathematics

2 answers:

Nana76 [90]3 years ago

5 0

Answer:

160 not 16

Step-by-step explanation:

Novay_Z [31]3 years ago

4 0

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

$z^{2}=\frac{Ak}{Aj}$

we have

$z=4$

substitute

$4^{2}=\frac{Ak}{Aj}$

$16=\frac{Ak}{Aj}$

$Ak=16Aj$

therefore

The area of triangle K is 16 times greater than the area of triangle J

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

For a school play, the teacher asked the class to set up chairs in 20 rows with 25 chairs in each row. After setting up all the

pantera1 [17]

20 rows * 25 chairs=500 chairs
500-5=495
Answer=495

6 0

4 years ago

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The train station runs trains every 30 minutes. Find the probability that a passenger who arrives at a random time will not have

DochEvi [55]

$|\Omega|=30\\ |A|=20\\\\ P(A)=\dfrac{20}{30}=\dfrac{2}{3}\Rightarrow \text{C}$

5 0

3 years ago

Kim Lee is buying a sedan that has a base price of $24,827. The options total $1,242, and the destination charge is $970. The de

romanna [79]

Answer:d

Step-by-step explanation:

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3 years ago

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Please someone help me answer the question below i need it by tomorrow.

Sauron [17]

72.9°

use tangent.

from the corner y look for the opposite and adjacent sides to your angle.

the opposite side from corner y is 13

the adjacent side from the corner is 4

tanY = 13/4

Y = inverse tangent of 13/4

72.897

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2 years ago