24 is not a prime factor, so it cannot be the be the prime factorization of a number
 
        
                    
             
        
        
        
Y=f(X)
At y-intercept, X=0
f(X)= 0^3-18(0)^3+107(0)-210
 = -210
        
             
        
        
        
Step-by-step explanation:
Use the standard form to write two equations using points A and B:
(
−
2
−
h
)
2
+
(
0
−
k
)
2
=
r
2
 
(
5
−
h
)
2
+
(
1
−
k
)
2
=
r
2
 
Because 
r
2
=
r
2
 , we can set the left sides equal:
(
−
2
−
h
)
2
+
(
0
−
k
)
2
=
(
5
−
h
)
2
+
(
1
−
k
)
2
 
Expand the squares using the pattern 
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
 
4
+
4
h
+
h
2
+
k
2
=
25
−
10
h
+
h
2
+
1
−
2
k
+
k
2
 
Combine like terms (noting that the squares cancel):
4
+
4
h
=
25
−
10
h
+
1
−
2
k
 
Move the k term the left and all other terms to the right:
2
k
=
−
14
h
+
22
 
Divide by 2
k
=
−
7
h
+
11
 [1]
Evaluate the given line at the center point:
2
h
+
k
−
1
=
0
 
Write in slope-intercept form
k
=
−
2
h
+
1
 [2]
Subtract equation [2] from equation [1]:
k
−
k
=
−
7
h
+
2
h
+
11
−
1
 
0
=
−
5
h
+
10
 
h
=
2
 
Substitute 2 for h in equation [2]
k
=
−
2
(
2
)
+
1
 
k
=
−
3
 
Substitute the center 
(
2
,
−
3
)
 into the equation of a circle using point A and solve for the value of r:
(
−
2
−
2
)
2
+
(
0
−
−
3
)
2
=
r
2
 
(
−
4
)
2
+
3
2
=
r
2
 
r
2
=
25
 
r
=
5
 
Substitute the center 
(
2
,
−
3
)
 and #r = 5 into the general equation of a circle, to obtain the specific equation for this circle:
(
x
−
2
)
2
+
(
y
−
−
3
)
2
=
5
2
 
        
             
        
        
        
Answer:
what are u asking?
Step-by-step explanation:
 
        
             
        
        
        
Yes because everything cancels out