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4 years ago

Four properties of water are listed.

Chemistry

2 answers:

velikii [3]4 years ago

6 0

The answer would be an.

IRISSAK [1]4 years ago

3 0

Answer:

B. 1 and 4

Explanation:

Chemical properties are those that cause the substance that reacts to undergo a chemical change. The product formed has completely different chemical property than the reactant. In a physical change the substance undergoes a physical change such as phase transition. In a physical change no new chemical substance is formed.

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What is the form of energy present in the pizza that we eat? group of answer choices mechanical chemical potential radiation.

PIT_PIT [208]

Answer:

Chemical energy

Explanation:

When the body eats food our bodies convert the stored energy (calories) to chemical energy, allowing us to function.

8 0

2 years ago

Explain what happens to energy and matter during a chemical reaction.

AlekseyPX

According to law of conservation of matter and energy, amount of both of them will remain same

4 0

3 years ago

Identify the single displacement reaction. C4H12 + 7O2 ⟶ 6H2O + 4CO2 2H2 + O2 ⟶ 2H2O Al2S3 ⟶ 2Al + 3S Cl2 + 2KBr ⟶ 2KCl + Br2

Varvara68 [4.7K]

Answer:- $Cl_2+2KBr\rightarrow 2KCl+Br_2$

Explanations:- The first reaction is combustion reaction as the hydrocarbon is burned in presence of oxygen to give carbon dioxide and water.

Second reaction is the synthesis reaction as in general a synthesis reaction looks like:

$A+B\rightarrow AB$

Third reaction is the decomposition reaction as it looks opposite of synthesis reaction.

$AB\rightarrow A+B$

In general, a single displacement reaction looks like:

$AB+C\rightarrow AC+B$

Fourth reaction is single replacement reaction as bromine is replaced by chlorine.

So, the correct choice is the last reaction, $Cl_2+2KBr\rightarrow 2KCl+Br_2$ .

8 0

3 years ago

A sample of O2 gas (2.0 mmol) effused through a pinhole in 5.0 s. It will take __________ s for the same amount of CO2 to effuse

ludmilkaskok [199]

Answer:

$\large \boxed{\text{5.9 s}}$

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of effusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Let CO₂ be Gas 1 and O₂ be Gas 2

Data:

M₁ = 44.01

M₂ = 32.00

Calculation

$\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}$

4 0

3 years ago

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Anastaziya [24]

Answer:

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5 0

3 years ago

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