Answer:
4 g after 58.2 years
0.0156 After 291 years
Explanation:
Given data:
Half-life of strontium-90 = 29.1 years
Initially present: 16g
mass present after 58.2 years =?
Mass present after 291 years =?
Solution:
Formula:
how much mass remains =1/ 2n (original mass) ……… (1)
Where “n” is the number of half lives
to find n
For 58.2 years
n = 58.2 years /29.1 years
n= 2
or 291 years
n = 291 years /29.1 years
n= 10
Put values in equation (1)
Mass after 58.2 years
mass remains =1/ 22 (16g)
mass remains =1/ 4 (16g)
mass remains = 4g
Mass after 58.2 years
mass remains =1/ 210 (16g)
mass remains =1/ 1024 (16g)
mass remains = 0.0156g
Answer:
The turnover number is the maximum substrate quantitiy converted to product per enzyme and per second. It can be calculate as follows:
![k_c = \frac{V_{max}}{[E]}](https://tex.z-dn.net/?f=k_c%20%3D%20%5Cfrac%7BV_%7Bmax%7D%7D%7B%5BE%5D%7D)
with ![[E]](https://tex.z-dn.net/?f=%5BE%5D)
active enzyme concentration.
In this case we have Vmax an data to calculate
![[E]=\frac{3.38*10^{-14}}{0.01 L}=3.38*10^{-12} M](https://tex.z-dn.net/?f=%5BE%5D%3D%5Cfrac%7B3.38%2A10%5E%7B-14%7D%7D%7B0.01%20L%7D%3D3.38%2A10%5E%7B-12%7D%20M%20)
Now 
it is not like any option.
If we assume that 
have the non usual units of 
and it is 
So we need divide by the moles of E (in place of [E])
Now 
(pass from 
to 
dividing by 60)
Moles of cu = mass/Ar
= 5/Ar
=ans
1 mole = 24dm3
Vol of cu = ans/1 × 24dm3
=ans
sorry i have no calculator with me now
Answer:
The correct option is;
(B) 1 s², 2s², 2p⁶, 3s², 3p³
Explanation:
The electron configuration is the outline of the electron arrangement about a nucleus
In the systemic pattern of electron arrangement within an atom, there are, s, p, d, f orbitals
The maximum number of electrons in an s, p and d orbital = 2, 6, and 10 respectively
Based on Aufbau's principle the electrons are arranged based on the order of their energy level
The charge is presented by the number of electrons in the outermost shell, an element able to form an ion of charge of -3 will gain 3 electrons to complete its outermost shell
Among the options given, option B is the only option that has the capacity to take the electrons to complete the number of electrons in the p orbital outermost shell to 6 from 3, that is 3p³ + 3e⁻→ 3p⁶.
The reaction is missing the Zn(s) in the reactants. The stoichiometry of the copper/zinc is 1 mole to 1 mole
