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worty [1.4K]
3 years ago
9

How many moles of magnesium chloride (mgcl2) are in 1.31 l of 0.38 m mgcl2?

Chemistry
1 answer:
Mumz [18]3 years ago
5 0
Molarity can be defined as the number of moles dissolved in 1 L of solution.
The molarity of MgCl₂ is 0.38 mol/L
In 1 L of MgCl₂ solution, amount go 0.38 moles is dissolved.
Therefore in 1.31 L of MgCl₂  - 0.38 mol /1 L x 1.31 L = 0.4978 mol rounded off  is 0.50 mol
In 1.31 L of solution, amount of 0.50 mol of MgCl₂ is present.
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7 0
3 years ago
How many pounds of ice are required to absorb 4900 kJ of heat as the ice melts? The heat of fusion of water is 0.334 kJ/g.
Goshia [24]

Answer:

m = 32.34 pounds of ice.

Explanation:

In this case we need to use the following expression of heat:

q = m * ΔHf   (1)

Where:

q: heat absorbed in J or kJ

m: mass of the compound in g

ΔHf: heat of fusion of the water in kJ/g

We are asked to look for the mass of ice in pounds, so after we get the grams, we need to convert the grams to pounds, using the following conversion:

1 pound --------> 453.59 g   (2)

So, we have the heat and heat of fusion, from (1) let's solve for the mass, and then, using (2) the conversion to pounds:

q = m * ΔHf  

m =  q / ΔHf

m = 4900 / 0.334 = 14,670.66 g of ice

Now, the conversion to pounds:

m = 14,670.66 g * 1 pound/453.59 g

<h2>m = 32.34 pounds of ice.</h2>

Hope this helps  

5 0
2 years ago
Viscous a chemical or physical property
Ahat [919]

Answer:

chemical

Explanation:

4 0
2 years ago
A rock weighing 26.0g placed graduated cylinder displacing the volume from 13.12ml to 25.3ml what is the density of the rock in
tia_tia [17]

density = mass /volume

1)mass of rock = 26.0 gram

2)volume of rock = volume of water it has displaced= 25.3-13.12 = 12.18

put the value of mass and volume in first equation and get the density value

3 0
3 years ago
What mass of hbr (in g) would you need to dissolve a 3.4 −g pure iron bar on a padlock?
vivado [14]

<u>Given:</u>

Mass of pure iron (Fe) = 3.4 g

<u>To determine:</u>

Mass of HBr needed to dissolve the above iron

<u>Explanation:</u>

Reaction between HBr and Fe is

Fe + 2HBr → FeBr₂ + H₂

Based on the reaction stoichiometry-

1 mole of Fe reacts with 2 moles of HBr

# moles of Fe = mass of Fe/atomic mass of Fe = 3.4/56 g.mol⁻¹ = 0.0607 moles

Therefore # moles of HBr = 2*0.0607 = 0.1214 moles

Molar mass of HBr = 81 g/mole

Mass of HBr = 0.1214 moles * 81 g/mole = 9.83 g

Ans: Mass of HBR required is 9.83 g

5 0
3 years ago
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