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Serggg [28]
3 years ago
10

Which is a component of John Dalton’s atomic theory?

Chemistry
2 answers:
navik [9.2K]3 years ago
8 0

Answer: lol the answer is A

Explanation:

i’m just smart like that , thought i should give y’all a clue

Alexus [3.1K]3 years ago
5 0

Answer:

The ratio of atoms in a compound is fixed.

Explanation:

its a

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17 Which compound has the strongest hydrogen bonding between its molecules?
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(3) HF. The strength of hydrogen bonding between molecules depends on the difference in the electronegativities of each atom in the molecule. Since fluorine is the most electronegative element, HF has the strongest hydrogen bonding.
6 0
2 years ago
An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The
Nataly_w [17]

Answer:

67

Explanation:

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3 years ago
How much heat will be absorbed by 395g of water when it's temperature is raised by 55°C​
Firdavs [7]

Answer:

\boxed{\text{91 kJ}}

Explanation:

The formula for the heat released is

q = mCΔT

Data:

 m = 395 g

 C = 4.184 J·°C⁻¹g⁻¹

ΔT = 55 °C

Calculations:

q = 395 × 4.184 × 55 = 91 000 J = 91 kJ

The water will absorb \boxed{\textbf{91 kJ}} of energy.

3 0
3 years ago
How does the atomic radius increase?
Helen [10]

Answer:

increases as you move down a group as the number of electrons increases. Therefore, the atomic radius increases as the group and energy levels increase

Explanation:

5 0
2 years ago
Using the equations
Anna [14]

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

<h3 /><h3>FIRST STEP</h3>

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

<h3>SECOND STEP</h3>

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

<h3>THIRD STEP</h3>

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

<h3>SUMMARY</h3>

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

Learn more about molar enthalpy:

  • <u>brainly.com/question/5976752?referrer=searchResults </u>
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7 0
2 years ago
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