Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
204204 - 16 = 204188
204188 / 4 = 51,047
width = 51,047
length = 51,055
Answer:
D) 24x + 52
Step-by-step explanation:
The perimeter of the purple rectangle is
P =2(l+w)
=2 (4x+5 + 2x+7)
Combine like terms
=2 (6x+12)
Distribute
= 12x +24
The perimeter of the white rectangle is
P =2(l+w)
P =2(3x+14 +3x)
Combine like terms
=2(6x+14)
Distribute
12x +28
Add the perimeters
12x +24 + 12x +28
24x +52
Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:
![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)
Is 21 because volume you add them up
