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FrozenT [24]
3 years ago
13

What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m

Mathematics
1 answer:
son4ous [18]3 years ago
6 0

In the isosceles trapezoid ABCD, draw two perpendiculars AM and BL from A and B to the side CD.  

Now, LM = BA = 5 m  

CD = CL + LM + MD

       = CL + 5 + CL (CL = MD)

      = 2CL + 5  

But, CD = 11

Therefore, 2CL + 5 = 11

2CL = 11 - 5

       = 6

CL = 6/2 = 3m

MD = 3m

Now, consider the right triangle AMD.

We have,  

AM^{2} = AD^{2} - MD^{2}

                  = 4^{2} - 3^{2}

                  = 16 - 9

                 = 7

Hence, height of the isosceles trapezoid = AM = \sqrt{7} m

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<u>Step-by-step explanation:</u>

Coterminal means it is in the exact same spot on the Unit Circle but one <em>or more </em>rotations clockwise <em>or counterclockwise.</em>

Since one rotation = 360°, add or subtract that from the given angle until you get a positive <em>or negative</em> number.

10) 255° + 360° = 615°     (this is a POSITIVE coterminal angle to 255°)

     255° - 360° = -105°     (this is a Negative coterminal angle to 255°)

12) -800° + 360° = -440°   (this is a Negative coterminal angle to -800°)

    -440° + 360° =  -80°      (this is a Negative coterminal angle to -800°)

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3 years ago
A rectangle has a height of c^3+6c^2+2c and a width of c^2+1
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Answer:

A = c^5+6c^4+3c^3+6c^2+2c

Step-by-step explanation:

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Here we are given height . Assuming it to be one of the side of the rectangle , we will do the further calculation

Hence one side is

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adding similar terms

c^5+6c^4+3c^3+6c^2+2c

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