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3 years ago

Does anyone know the answer to this?

Mathematics

1 answer:

Klio2033 [76]3 years ago

7 0

Try photo math
It help u

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Write a sentence to explain what a cube root of a number means.

svetlana [45]

Answer:

The cube root of a number is a special value that when used in a multiplication three times it gives that number.

Step-by-step explanation:

Example:

3 x 3 x 3

9 x 3 = 27

$3^{3}$

5 0

3 years ago

2/9 of Mrs. Hanak's 18 students are Minton walkers. How many students dismiss as Minton walkers?

Alex

Answer:

2*2=4, 9*2=18, so 2/9 = 4/18, 4 students are Minton walkers.

Step-by-step explanation:

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3 years ago

Let f(x)=8x^3 -22x^2 and g(x)=4x-3. find f(x)/g(x)

Gala2k [10]

Answer:

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3 years ago

Lindsey bought a package of 3 chocolate cookies. Each cookie weighed 0.3 ounces. How much did the 3 cookies weigh all together?

konstantin123 [22]

Answer:

0.9 ounces

Step-by-step explanation:

Each cookie weighs 0.3 ounces and there are 3 cookies. So multiply 0.3 by 3 and you get 0.9.

hope this helps, brainliest appreciated!

3 0

2 years ago

Read 2 more answers

Use the quadratic formula to solve for the roots in the following equation. 4x 2 + 5x + 2 = 2x 2 + 7x – 1

Natali5045456 [20]

Answer:

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

Step-by-step explanation:

$4x^2 + 5x + 2 = 2x^2 + 7x - 1$

We need to solve the equation to find the roots using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Rearranging the above equation:

$4x^2 -2x^2+ 5x-7x + 2+1 =0$

$2x^2 -2x + 3 =0$

Where a =2 , b=-2 and c =3 Putting values in quadratic equation and solving:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(3)}}{2(2)}\\x=\frac{2\pm\sqrt{4-24}}{4}\\x=\frac{2\pm\sqrt{-20}}{4}\\\sqrt{-20} \,\,can\,\,be\,\, written\,\, as\,\, 2\sqrt{-5}\\ x=\frac{2\pm2\sqrt{-5}}{4}\\x=\frac{2+2\sqrt{-5}}{4} \,\, and \,\, x=\frac{2-2\sqrt{-5}}{4}\\x=\frac{2(1+\sqrt{-5})}{4} \,\, and \,\, x=\frac{2(1-\sqrt{-5})}{4}\\ x=\frac{1+\sqrt{-5}}{2} \,\, and \,\, x=\frac{1-\sqrt{-5}}{2}\\As \,\,we\,\, know\,\, \sqrt{-1} = i \\$

$x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

6 0

3 years ago