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Dmitry [639]
4 years ago
11

Which of the following can be determined by studying the spectrum of a star?

Physics
1 answer:
Alex73 [517]4 years ago
3 0
The right answer is 
  
all of the above 
 
good luck

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1. When human bones are brittle due to eating too much dairy food, what is this called?
Firdavs [7]

Answer:

1. Osteoporosis

2. Dehydration

3. Atherosclerosis

4. Aerobic exercise

5. Heart disease, obesity, diabetes and high blood pressure

6. Coronary heart disease, colorectal cancer, diabetes

Explanation:

1. Osteoporosis is the condition of the bones when they become easily fractured and less dense, such that injuries to the bones are likely to cause disability or pain

2. The bod becomes dehydrated in the event that there is insufficient water for proper functioning of the organs due to the loss of more water than the water that is taken in or absorbed.

3. Atherosclerosis is the building of plaque on the inside and outside of the walls of the arteries by cholesterol, fat, and other compounds in the blood often being taken as a problem or undesirable condition of the heart.

4. Processed foods are those that contain chemicals (that give them a good taste) in proportions that can cause illnesses

5. Taking large quantities of (red) meat such as burgers, or barbecued red meat,  can lead to type 2 diabetes, cancers and stroke

6 0
3 years ago
What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases? a It decreases b
kupik [55]

Answer:

It remains the same

Explanation:

It remains the same. This is because the number of protons doesn't change and the number of protons determines the atomic number.

8 0
2 years ago
The slope on a distance-time graph shows a ball moving from 20 m to 40 m in 1 s and from 40 m to 80 m in the next second
eduard

The ball is accelerating

Explanation:

On a distance-time graph, the slope of the graph represents the speed of the object represented.

Let's therefore calculate the slope (so, the speed of the ball) in the two intervals given.

In the first second, we have:

\Delta y = 40 - 20 = 20 m\\\Delta x = 1 s

So the average speed is

v_1 = \frac{\Delta y}{\Delta x}=\frac{20}{1}=20 m/s

In the next second, we have:

\Delta y = 80 - 40 = 40 m\\\Delta x = 1 s

So the average speed is

v_2 = \frac{\Delta y}{\Delta x}=\frac{40}{1}=40 m/s

We notice that the speed of the ball has increased from 20 m/s in the first second to 40 m/s in the next second: this means that the speed of the ball is increasing, and therefore, the ball is accelerating.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

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#LearnwithBrainly

8 0
3 years ago
A group of workers applied 10.0 networks of force to move a crate 20.0 meter. Calculate the work
olga2289 [7]

The work done is 200 J

Explanation:

The work done by a force applied to move an object is given by:

W= F d cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:

F = 10.0 N

d = 20.0 m

\theta=0^{\circ}

Therefore, the work done is:

W=(10.0)(20.0)(cos 0)=200 J

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4 0
4 years ago
determine the greates possile acceleration of the 975 kg race car so that its front wheels do not leace the gorund
wolverine [178]

<u>Answer</u>:

The greatest possible acceleration of the car is a_G= 6.78 m/s^2

<u>Explanation</u>:

N_A+N_B-Mg = 0

-N_Aa +N_B(b-a)- \mu_s N_Bh - \mu_s N_Ah = 0

0.8N_B +0.8N_A = 975a_G

N_A+N_B = 9564.75 -------------(1)

-N_A(1.82) + N_B(2.20 -1.82) -0.9N_B(0.55)-0.8N_A(0.55)=0

-N_A(1.82) +0.38 N_B -0.44N_B -0.44N_A=0

-2.26N_A -0.06N_B= 0 ----------------(2)

Solving the equation (1) and(2)

N_A + N_B = 9564.75

-2.26N_A-0.06N_B=0

N_A = -260.85N

N_B = 9825.60N

\mu_s N_B + \mu_s N_A = 975a_G

0.8(9825.60)+0.8(-260.85) = 975a_Ga_G=\frac{7651.8}{975}a_G_1=7.4848m/s^2

Next lets assume that the front wheels contact with the ground N_A = 0

F_B = Ma_G

N_B = M_g

N_B - M_g = 0

N_B(b-a) –F_Bh = 0

F_B = 975a_G

N_B-975(9.8) = 0

N_B=9564.75N

9564.75(2.20 -1.82) -F_B(0.55)=0

\frac{3634.605}{0.55}=F_B

F_B = 6608.3

F_B = Ma_G

6608.3 = 975a_G

a_G = 6.7778 m/s^2

a_G_2 = 6.78m/s^2

Choosing the critical case

a_G = min(a_G_1 ,a_G_2)

a_G = min(7.848, 6.78)

a_G= 6.78 m/s^2

3 0
4 years ago
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