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EastWind [94]
3 years ago
12

Define critical angle​

Physics
1 answer:
lukranit [14]3 years ago
6 0

Answer:

Critical angle is a angle of incidence, for which refraction is 90 degree, this is a least angle of incidence at which total reflection takes place, please mark me Brainliest

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A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child appl
lozanna [386]

Answer:

The value is KE = 259.6 \  J

Explanation:

From the question we are told that

     The weight of the horizontal solid disk is  W = 805 \  N

      The radius of the horizontal solid disk is  r =  1.58 \  m

      The force applied by the child is  F  =  49.5 \  N

       The time considered is  t =  2.95 \  s

Generally the mass of the  horizontal solid disk is mathematically represented as

          m_h  =  \frac{W}{ g}

=>       m_h  =  \frac{805}{ 9.8 }

=>       m_h  =  82.14 \  N

Generally the moment of inertia  of the horizontal solid disk is mathematically represented as  

         I  =  \frac{1}{2} *  m *  r^ 2

=>      I  =  \frac{1}{2} *  82.14 *   1.58^ 2  

=>      I  =  102.5 \  kg \cdot m^2

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

           T =  I  *  \alpha   =  F *  r

=>         \alpha  =  \frac{ F  *  r }{ I }

=>         \alpha  =  \frac{  49.5  *   1.58 }{  102.53 }

=>         \alpha  = 0.7628

Gnerally from kinematic equation we have that

         w =  w_o  +  \alpha t

Here  w_o is the initial angular velocity velocity of the horizontal solid disk  which is  w_o  =  0\   rad/s

So

           w =   0  +  0.7628 * 2.95

=>        w =  2.2503 \  rad/s

Generally the kinetic energy is mathematically represented as

        KE =  \frac{1}{2}  *  I  *  w^2

=>      KE =  \frac{1}{2}  * 102.53  *  2.2503 ^2

=>      KE = 259.6 \  J

8 0
3 years ago
Un pez llamado PARGO ROJO vive a grandes profundidades. Si se pesca, al salir a la superficie puede tomar el aspecto de la foto
zalisa [80]

Answer:

Hay diversas leyes que podemos usar acá.

Acá sabemos que la vejiga aumenta su tamaño al reducir la presión, esto tiene sentido, pues al haber menos presión, hay menos fuerza que comprime la vejiga, lo que le permite aumentar su volumen.

Acá tenemos una relación inversa de la forma: V = K/P

Una relación inversa donde la presión esta en el denominador y K es un termino que no depende ni del volumen ni de la presión.

Entonces, a medida que aumenta P, el denominador aumenta, por lo que el valor del volumen decrece.

Un ejemplo de una ecuación similar es la del gas ideal, por ejemplo, para un gas ideal dentro de un globo de volumen V para una dada presión P:

V = nRT/P

donde n es el numero de moles, R es la constante termodinámica y T es la temperatura, acá podemos ver que esta ecuación tiene la misma forma fundamental que la escrita arriba.

7 0
3 years ago
Hi can someone PLEASE HELP ME. I asked this question 3 times already and haven't gotten an answer. I give brainliest to whoever
Serggg [28]
HCl + NaOH -> H2O + NaCl

CaCO3 + KI -> K2CO2 + CaI2

AlF3 + Mg(NO3)2 -> Al(NO3)3 + MgF2
7 0
3 years ago
Read 2 more answers
Which statement describes the relationship between the rate of reaction and the temperature?
patriot [66]

PM me the statements, and i'll answer it then.

7 0
3 years ago
A young kid of mass m = 36 kg is swinging on a swing. The length from the top of the swing set to the seat is L = 3.5 m. The boy
lara31 [8.8K]

Answer:

Explanation:

Given

mass of boy=36 kg

length of swing=3.5 m

Let T be the tension in the swing

At top point mg-T=\frac{mv^2}{r}

where v=velocity needed to complete circular path

Th-resold velocity is given by mg-0=\frac{mv^2}{r}

v=\sqrt{gr}=\sqrt{9.8\times 3.5}=5.85 m/s

So apparent weight of boy will be zero at top when it travels with a velocity of v=\sqrt{gr}

To get the velocity at bottom conserve energy at Top and bottom

At top E_T=mg\times 2L+\frac{mv^2}{2}

Energy at Bottom E_b=\frac{mv_0^2}{2}

Comparing two as energy is conserved

v_0^2=4gl+gl

v_0^2=5gL

v_0=\sqrt{5gL}=13.09 m/s

Apparent weight at bottom is given by

W=\frac{mv_0^2}{L}-mg=\frac{36\times 13.09^2}{3.5}+36\times 9.8=2115.23 N

6 0
3 years ago
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