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Amiraneli [1.4K]
3 years ago
5

An eagle is flying around and its velocity v as a function of time t is given in the graph below where

Physics
1 answer:
ahrayia [7]3 years ago
8 0
I honestly don’t even know
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What happens when two waves meet while they travel through the same medium
Yuki888 [10]

Wave Interference or Interference of wave

7 0
3 years ago
How could you increase the amount of kenitic energy
Fiesta28 [93]

Answer:

As You know kinetic Energy is equal (mv^2)/2

You can increase it by increasing the mass(keeping the velocity)

Or You can add velocity

Explanation:

8 0
3 years ago
Can someone explain this please?<br> (:
topjm [15]

Answer:

a= kinetic energy vs. different masses at same speed, b= kinetic energy vs. same masses at different speeds

Explanation:

graphs are looking at speed so masses don't matter as much. same speed the whole time will equal same kinetic energy the whole time.

8 0
3 years ago
A cyclist maintains a constant velocity of
Feliz [49]
The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m


Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

3 0
3 years ago
Jessie draws a ray diagram to show how an image of a candle is produced by a concave mirror when the candle is placed in front o
irina1246 [14]
There are two rules of reflection for the concave mirror:
1)<span>Any incident ray traveling parallel to the principal axis on the way to the mirror will pass through the focal point upon reflection.
2)</span><span>Any incident ray passing through the focal point on the way to the mirror will travel parallel to the principal axis upon reflection.
Also, keep in that for concave mirror center of curvature is 2f.
Using these two rules we can construct the image. 
You should always use these two "special" rays, I will mark then 1 and 2 on the picture.
From the picture, we can see that if you place the object between the focus and vertex you get the virtual image.
The answer is: object should be between the focal point and the vertex</span>

8 0
3 years ago
Read 2 more answers
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