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SIZIF [17.4K]
3 years ago
7

Show that 551 is a rational by writing it in the form a/b, where a and b are integers

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

  551/1

Step-by-step explanation:

  551 = \dfrac{551}{1}

__

Any integer can be written as a rational number with a denominator of 1.

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Contrast and compare squares and rectangles
liberstina [14]

Answer:

I found this over the internet and hope it helps:

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Paladinen [302]

The value of x in the given equation is -\frac{4}{5}

From the question,

We are to solve the given equation

The given equation is

log_{6}(36) = 5x +6

This becomes

log_{6}(6^{2} ) = 5x +6

From one of the laws of logarithms, we have that

log_{x}(x^{2} ) = 2log_{x}(x)

and

log_{x}(x) = 1

∴ log_{6}(6^{2} ) = 5x +6 becomes

2log_{6}(6) = 5x +6

and

2(1)= 5x +6

2 = 5x +6

Now, subtract 6 from both sides

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∴ x = -\frac{4}{5}

Hence, the value of x in the given equation is -\frac{4}{5}

Learn more on solving equations here: brainly.com/question/11802986

4 0
2 years ago
Read 2 more answers
Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi on 19 gal
nika2105 [10]

Answer:

7 gallons were used for city driving.

Step-by-step explanation:

I am going to solve this question by a system of equations.

I am going to say that:

x is the number of gallons driven in the city.

y is the number of gallons driven in the highway.

19 gal of gas

This means that x + y = 19

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi.

This means that 13.2x + 25.3y = 396

How many of the gallons (to the nearest gallon) were used for city driving?

This is x

From the first equation, i will have

y = 19 - x

Replacing in the second equation

13.2x + 25.3y = 396

13.2x + 25.3(19 - x) = 396

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x = \frac{84.7}{12.1}

x = 7

7 gallons were used for city driving.

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3 years ago
Write 7 16/25 as a decimal.​
Burka [1]
Hi! your answer should be 7.64 if I am not mistaken
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