Determine whether the inequality is always, sometimes, or never true. 4x - 8 > 1 + 4(x+3)

Mathematics

2 answers:

DiKsa [7]3 years ago

6 0

Answer:

Never true

Step-by-step explanation:

Given inequality,

$4x - 8 > 1 + 4(x+3)$

$4x-8 > 1 + 4x + 12$

$4x-8 > 4x + 13$

$-8 > 13$ ( false )

Since, when after solving an equation or inequality we get a true statement then the equation or inequality has infinitely many solution or true for all numbers while if we get a false statement then the equation of inequality has no solution or not true.

Hence, the given inequality is never true.

kramer3 years ago

5 0

Never true because there is no solution

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3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

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So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$