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zhenek [66]
3 years ago
12

How do you write 9.88 ×10 square in standard form

Mathematics
1 answer:
KIM [24]3 years ago
8 0
U right 9.88•10 in standard form like 98800000000.
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Question attached,
alexandr1967 [171]

Answer:

Step-by-step explanation:

(a)\\ \\ (i)\ \sqrt{3}=3^p\\ \\ 3^{\frac{1}{2}}=3^p\\ \\ p=\frac{1}{2}\\ \\ (ii)\ \frac{1}{9}=3^q\\ \\ 3^{-2}=3^q\\ \\ q=-2\\ \\ (b)\\ \\ 3^{\frac{1}{2}(3^x)=\frac{1}{9}\\ \\ 3^{\frac{1}{2}+x}=3^{-2}\\ \\ \frac{1}{2}+x=-2\\ \\ x=-1.5

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3 years ago
If it is 7:20 am how many minutes until 7:46 am
exis [7]
26 minutes until 7.46am
6 0
4 years ago
Which of the statements supports the conclusion from the diagram and the GIVEN information.
uysha [10]
C) Adjacent angles whose exterior sides are perpendicular rays are complementary.

Complementary = add up to 90
Supplementary = add up to 180
7 0
3 years ago
Read 2 more answers
How do you simplify an Algebraic expression ?
NeTakaya

Answer:

You can solve one by... it's hard to explain So i'll just show you

Step-by-step explanation:

Here's an example,

2x+7=4+5x

First you subtract the variables on both sides (lower variable)

2x+7=4+5x

-2x       -2x

Which will leave you

7=4+3x

The subtract the whole number on each side (lower number)

7=4+3x

-4   -4

Which will leave you

3=+3x

Then you divide on both sides

3/3   3/3

which should leave you

x=1

5 0
3 years ago
Which of the following points is a solution to the system of equations x - y = 1 and -x + 3y = - 7?
kiruha [24]

Answer:

(-2,-3)

Step-by-step explanation:

Put the equations over each other.

\binom{x - y = 1}{ - x + 3y =  - 7 }

Subtract the x values.

\binom{ - y = 1}{3y =  - 7}

Subtract on both sides.

2y =  - 6

Divide on both sides.

y =  - 3

Insert the y value into one of the equations.

x - ( - 3) = 1

Get rid of the parenthesis.

x + 3 = 1

Subtract on both sides.

x =  - 2

<em>You</em><em> </em><em>could</em><em> </em><em>also</em><em> </em><em>individually</em><em> </em><em>plug</em><em> </em><em>in</em><em> </em><em>each</em><em> </em><em>solution</em><em> </em><em>into</em><em> </em><em>both</em><em> </em><em>equations</em><em> </em><em>to</em><em> </em><em>see</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>true</em><em>.</em>

7 0
2 years ago
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