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Ganezh [65]
3 years ago
9

Last week the cost of a pair of socks was $3.25. This week they are on sale for $1.95. What is the percent change from last week

to this week?
Tell whether this is an increase or a decrease then give the percent the value changed.
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

The socks are 40% off, and it is decreased to 60%.

Step-by-step explanation:

:))

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Andre45 [30]
<h3>Answer</h3>

First multiply everything by 27

-  \frac{4}{9} x =  \frac{16}{27}  =  \\ 27 \times ( -  \frac{4 }{9}x) = 27 \times  \frac{16}{27}

Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)

3 \times (   - \frac{4}{1} ) = 16

So now multiply again

3 \times ( - 4) =  - 12

And you have

- 12x = 16

x =  -  \frac{16}{12}  =  -  \frac{4}{3}

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4 years ago
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How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?
defon
\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1

(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1

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\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}



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Answer:

3125

Step-by-step explanation:

Cuz it is. I 4=5

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