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3 years ago

At –45oC, 71 g of fluorine gas take up 6843 mL of space. What is the pressure of the gas, in kPa?

1 answer:

4 0

The moles of fluorine present are 71/19 = 3.74
Now, we know that one mole of gas at 273 K and 101.3 kPa (S.T.P.) occupies 22.4 liters
Volume of 3.74 moles at S.T.P = 3.74 x 22.4
Volume = 83.776 L = 83,776 mL

Now, we use Boyle's law, that for a given amount of gas,
PV = constant

P x 6843 = 101.3 x 83776
P = 1,240 kPa

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Which of the following statements is true?

eduard

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Lines of latitude are used to divide Earth into 24 time zones

Explanation:

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3 years ago

How do you solve this ?NH4+NO4->N2+O2+H2O2

ololo11 [35]

I'm assuming you wanted this equation balanced? If you typed it correctly, it's already balanced for you. :)

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3 years ago

Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution

dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

1. we calculate the moles of NaOH

$\tt mol=\dfrac{mass}{MW}$

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

$\tt mol=\dfrac{40~g}{40~g/mol}=1~mol$

2. Molarity(M)

$\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16$

5 0

3 years ago

A mixture of He , Ar , and Xe has a total pressure of 3.00 atm . The partial pressure of He is 0.200 atm , and the partial press

yaroslaw [1]

The partial pressure of Xe is 2.60atm

The sum of the partial pressures is equal to the total pressure. Ptotal = P1 + P2 + P3... .To calculate the partial pressure of one of the components of a mixture, subtract the sum of known partial pressures of the other components from the total pressure.

Given the values of

PHe=0.20 atm

PAr=0.20 atm

Ptotal=3.00 atm

We need to find PXe

Solution: Determine the sum of the partial pressures of helium and argon, then subtract the sum from the total pressure.

PHe+PAr =0.20 atm + 0.20=0.400 atm

PXe=3.00atm−0.400=2.60 atm

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

According to Dalton's Law, a perfect gas mixture's total pressure equals the sum of its constituent gases' individual partial pressures.

The thermodynamic activity of a gas's molecules is gauged by its partial pressure.

Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

This general characteristic of gases holds true in biological chemical interactions involving gases.

Hence the partial pressure of Xe is 2.60atm

Learn more about partial pressure here

brainly.com/question/19813237

#SPJ4

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2 years ago

El NaCI corresponde a un elemento?

Schach [20]

Answer:

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Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

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3 years ago