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inn [45]
2 years ago
11

A mixture of He , Ar , and Xe has a total pressure of 3.00 atm . The partial pressure of He is 0.200 atm , and the partial press

ure of Ar is 0.200 atm . What is the partial pressure of Xe ? Express your answer to three significant figures and include the appropriate units.
Chemistry
1 answer:
yaroslaw [1]2 years ago
5 0

The partial pressure of Xe is 2.60atm

The sum of the partial pressures is equal to the total pressure. Ptotal = P1 + P2 + P3... .To calculate the partial pressure of one of the components of a mixture, subtract the sum of known partial pressures of the other components from the total pressure.

Given the values of

PHe=0.20 atm

PAr=0.20 atm

Ptotal=3.00 atm

We need to find  PXe

Solution: Determine the sum of the partial pressures of helium and argon, then subtract the sum from the total pressure.

PHe+PAr =0.20 atm + 0.20=0.400 atm

PXe=3.00atm−0.400=2.60 atm

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

According to Dalton's Law, a perfect gas mixture's total pressure equals the sum of its constituent gases' individual partial pressures.

The thermodynamic activity of a gas's molecules is gauged by its partial pressure.

Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

This general characteristic of gases holds true in biological chemical interactions involving gases.

Hence the partial pressure of Xe is 2.60atm

Learn more about partial pressure here

brainly.com/question/19813237

#SPJ4

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Answer:

6.07 L

Explanation:

It appears that the reading has been made at constant pressure .

At constant pressure , the gas law formula is

V/T = constant  V is volume and T is temperature of the gas.

V₁ / T₁ = V₂ / T₂

V₁ = 6.6 L ,

T₁ = 40°C

= 273 + 40

= 313 K

T₂ = 15+ 273

= 288K

V₂ = ?

Putting the values in the formula above

6.6 / 313  = V₂ / 288

V₂ = 6.07 L.

8 0
3 years ago
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8 0
3 years ago
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6 0
2 years ago
What is the answer for chemestry when it says 1.204 times 10^24
Sphinxa [80]

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6 0
3 years ago
What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall r
Sergeu [11.5K]
Answer:
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Explanation:

The balance equation is as follow,

<span>                   5 Ag</span>⁺ + Mn⁺²<span> + 4 H</span>₂O    →<span>    5 Ag + MnO</span>₄⁻<span> + 8 H</span>⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
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Result:
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4 0
3 years ago
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