Answer:
0.36 M
Explanation:
Let's consider the following neutralization reaction.
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
25 mL of 0.83 M NaOH reacted. The moles of NaOH that reacted are:
0.025 L × 0.83 mol/L =0.021 mol
The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 0.021 moles.
0.021 moles are contained in 58 mL of HCl. The molar concentration of HCl is:
M = 0.021 mol/0.058 L
M = 0.36 M
Anemia is essentially an iron deficiency so the element found in the liver preventing it would be Fe (iron).
Answer:
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.
Explanation:
- This is an acid-base reaction which produces salt and water according to the balanced equation:
<em>2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.</em>
<em></em>
it is clear that 2.0 moles of KOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of K₂SO₄ and 2.0 moles of H₂O
<u>Answer:</u> The experimental van't Hoff factor is 1.21
<u>Explanation:</u>
The expression for the depression in freezing point is given as:
where,
i = van't Hoff factor = ?
= depression in freezing point = 0.225°C
= Cryoscopic constant = 1.86°C/m
m = molality of the solution = 0.100 m
Putting values in above equation, we get:
Hence, the experimental van't Hoff factor is 1.21
