Answer:
0.1738 M
Explanation:
Let's consider the neutralization reaction between NaOH and HBr.
NaOH + HBr → NaBr + H₂O
The moles of HBr are:
14.76 × 10⁻³ L × 0.4122 mol/L = 6.084 × 10⁻³ mol
The molar ratio of NaOH to HBr is 1:1. In the endpoint, they have reacted completely, so the moles of NaOH were 6.084 × 10⁻³ mol before the reaction.
The molarity of NaOH is:
M = 6.084 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.1738 M
Write the formula of the compound.
Write the numbers of each atom in the formula. Insert the relative atomic mass for each type of atom. Calculate the total mass for each element.
Add up the total mass for the compound.
Element Symbol Mass Percent
Oxygen O 16.985%
Potassium K 83.015%
Answer:
V = 0.63 L
Explanation:
To solve this problem, we need to use the Charle's law which is a law that involves temperature and volume, assuming we have a constant pressure. The problem do not state that the pressure is being altered, so we can safely assume that the pressure is constant (Maybe 1 atm).
Now, as the pressure is constant, the Charle's law is the following:
V₁ / T₁ = V₂ / T₂ (1) V is volume in Liter, and T is temperature in Kelvin.
Using this law with the given data, we solve for V₂:
V₂ = V₁T₂ / T₁
Before we use this expression, let's convert the temperatures to Kelvin:
T₁ = 19 + 273 = 292 K
T₂ = 250 + 273 = 523 K
Now, let's calculate the volume of the balloon:
V₂ = 0.35 * 523 / 292
<h2>
V₂ = 0.63 L</h2>
Answer:
Helium (He), Neon (Ne), Argon (Ar)
Explanation:
they are in group 18 elements.
because of their non-reactivity they are called the intern gases or Noble gases.