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3 years ago

Solve it! Hurry Will mark as brainliest IF U TRY TO get the points free i would report u

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

verified

ad-work [718]3 years ago

7 0

Answer:

Give him or her brainlist

Step-by-step explanation:

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3 years ago

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2 years ago

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Find the term indecent of x in the expansion of (x^2-1/x)^6

Mars2501 [29]

By the binomial theorem,

$\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}$

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0 ===> 3k = 12 ===> k = 4

which corresponds to the constant coefficient

$\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}$

3 0

3 years ago

Need help solving homework

Lilit [14]

3 + 2 = 1 + 4
2 + 15 = 10 + 7
8 + 9 = 19 - 2
12 - 7 = 14 - 9

Hope this helped!

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2 years ago

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Laquita practiced 60 math facts. Kinman practiced 15 more facts than Laquita. How many math facts did they practice in all?

Afina-wow [57]

Answer:

They practiced a total of 75 math facts in all!

60 + 15 = 75 :D

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3 years ago