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3 years ago

Name two fluid technologies that make use of air

Chemistry

2 answers:

Temka [501]3 years ago

6 0

Answer:

The correct answers are Plate Picker and Drill.

Explanation:

In the platen picker, the platens pass from an oblique conveyor to a horizontal conveyor belt. A double-acting cylinder with a hollow piston rod, integrated suction cup, and suction nozzle is used to change from one lane to the other. The working pressure of the vacuum system is 4 Bar.

In a drill, the workpieces are held in place by a pneumatic cylinder. When doing so, the workpiece must first be clamped with a pressure of 3 bar for easy adjustment, then clamped with a pressure of 6 bar. Once the drilling phase has been completed, the clamping cylinder is returned. The clamping opening must not be possible during the drilling process.

Have a nice day!

Aleks [24]3 years ago

5 0

Two fluid technologies that make use of air are an air compressor and desk chair

The air compressor is used for such things as to clean out drill holes in rock to clear the cuttings and also an airbag in cars for safety of the passengers to prevent them from hitting their head on the dash or the windshield in case of a car accident.

Explanation:

An compressor could be a device that converts power into P.E. hold on in pressurized air (i.e., compressed air). By one in all many ways, an compressor forces additional and additional air into a vessel, increasing the pressure.

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Mixture of 120 grams of KClO3 and 300 grams of water until all of the KClO3 has dissolved. At what temperature does this occur?

lozanna [386]

240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

Explanation:

As per the solubility curve graph of different salts dissolved in 100 g of water, it can be noted that the KClO₃ gets saturated at 100 °C with the solubility of 59 g in it. But here the water is taken as 300 g and the salt is taken as 120 g. The graph shows the solubility of grams of salt in 100 g of water.

So, then we have to find what is the gram of salt present in 100 g of water for the present sample.

300 g of water contains 120 grams of salt.

Then, 1 g of water will contain $\frac{120}{300}$ g of salt.

Then, 100 g of water will contain $\frac{120}{300}*100$ of salt. This means, 100 g of water will contain 40 g of salt in it.

Then, if we check the graph, the corresponding x-axis point on the curve for the y-axis value of 40 g will give us the temperature required to dissolve the salt in water. So 80°C will be required to dissolve 40 g of salt in 100 g of water.

Then, in order to get the temperature required to dissolve 120 g in 300 g of water, multiply the temperature by 3, which will give the result as 80×3=240 °C.

So, 240°C is required to dissolve 120 grams of KClO₃ in 300 g of water.

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