All categories

3 years ago

Which of these salts is insoluble in water?

Chemistry

1 answer:

egoroff_w [7]3 years ago

3 0

Answer:

Explanation:

You might be interested in

Calculate the silver ion concentration in a saturated solution of silver(i) sulfate (ksp = 1.4 × 10–5).

deff fn [24]

Answer:

= 0.030 M

Explanation:

We can take x to be the concentration in mol/L of Ag2SO4 that dissolves

Therefore; concentration of Ag+ is 2x mol/L and that of SO4^2- x mol/L.

Ksp = 1.4 x 10^-5

Ksp = [Ag+]^2 [SO42-]

= (2x)^2(x)

= 4x^3

Thus;

4x^3 = 1.4 x 10^-5

= 0.015 M

molar solubility = 0.015 M

But;

[Ag+]= 2x

Hence; silver ion concentration is

= 2 x 0.015 M

= 0.030 M

6 0

3 years ago

A hot toluene stream, which has mass flow rate of 8.0 kg/min, is cooled by cooling water in a cocurrent heat exchanger; its temp

Alex Ar [27]

Complete Question

The complete question is shown on the first question

Answer:

a) The duty of the heat exchanger is given as 6.8658 KJ /sec

b) The temperature of the water leaving the exchanger is TOUT = 29.84 ⁰C

c) The log mean difference is given as TZ = 47.317 ⁰ C

d) the UA value is UA = 145.10

Explanation:

The explanation is uploaded on the first and second ,third and fourth image

3 0

3 years ago

How many atoms are in 1.50 moles of fluorine gas

evablogger [386]

1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas

8 0

3 years ago

Consider the model of the nitrogen atom.

liq [111]

Answer:

1s2 2s2 2p3

Explanation:

we know that the number of electrons in an atom is equal to number of protons. So the number of electrons here is 7.

Using Moller chart, the electronic configuration is writen by the electrons first enterring into 1s then into 2s after 2p. The s orbital accomodates maximum of 2 electrons.

∴ for atomic no. 7 nitrogen atom, electronic configuration is 1s2 2s2 2p3.

5 0

3 years ago

Read 2 more answers

A colorless liquid has a molar mass of 60.01 g/mol. When the liquid was analyzed, it was 46.7% nitrogen and 53.3% oxygen. What i

MAXImum [283]

first we have to find the empirical formula of the compound

empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

therefore number of atoms are

N - 1

O - 1

empirical formula is - NO

mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

molecular formula is actual composition of elements in the compound

molecular mass - 60.01 g/mol

number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

there are 2 empirical units

2(NO)

molecular formula = N₂O₂

6 0

3 years ago