Question

What volume of a 1.50 m hcl solution should you use to prepare 2.00 l of a 0.100 m hcl solution?

Answer 1

(2.00 L) x (0.100 M HCl) / (1.50 M HCl) = 0.133 L

Answer 2

Answer : The volume of a 1.50 M HCl solution use should be 0.133 L

Explanation :

Using neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = concentration of HCl solution = 1.50 M

$M_2$ = concentration of another HCl solution = 0.100 M

$V_1$ = volume of HCl solution = ?

$V_2$ = volume of another HCl solution = 2.00 L

Now put all the given values in the above law, we get:

$1.50M\times V_1=0.100M\times 2.00L$

$V_1=0.133L$

Therefore, the volume of a 1.50 M HCl solution use should be 0.133 L