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Lelechka [254]
3 years ago
10

What volume of a 1.50 m hcl solution should you use to prepare 2.00 l of a 0.100 m hcl solution?

Chemistry
2 answers:
katen-ka-za [31]3 years ago
8 0
<span>(2.00 L) x (0.100 M HCl) / (1.50 M HCl) = 0.133 L</span>
Harman [31]3 years ago
5 0

Answer : The volume of a 1.50 M HCl solution use should be 0.133 L

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = concentration of HCl solution = 1.50 M

M_2 = concentration of another HCl solution = 0.100 M

V_1 = volume of HCl solution = ?

V_2 = volume of another HCl solution = 2.00 L

Now put all the given values in the above law, we get:

1.50M\times V_1=0.100M\times 2.00L

V_1=0.133L

Therefore, the volume of a 1.50 M HCl solution use should be 0.133 L

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In the laboratory you dissolve 19.4 g of potassium acetate in a volumetric flask and add water to a total volume of 125 mL. What
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The molarity of the potassium acetate solution given the data is 1.584 M

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of CH₃COOK</h3>
  • Mass of CH₃COOK = 19.4 g
  • Molar mass of CH₃COOK = 98 g/mol
  • Mole of CH₃COOK =?

Mole = mass / molar mass

Mole of CH₃COOK = 19.4 / 98

Mole of CH₃COOK = 0.198 mole

<h3>How to determine the molarity of CH₃COOK</h3>
  • Mole of CH₃COOK = 0.198 mole
  • Volume = 125 mL = 125 / 1000 = 0.125 L
  • Molarity of CH₃COOK = ?

Molarity = mole / Volume

Molarity of CH₃COOK = 0.198 / 0.125

Molarity of CH₃COOK = 1.584 M

Learn more about molarity:

brainly.com/question/15370276

#SPJ4

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