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Gnoma [55]
3 years ago
9

The gauge pressure in your car tires is 2.50×10^5N/m22.50×10^5⁢N/m^2 at a temperature of 35.0ºC when you drive it onto a ferry b

oat to Alaska. What is their gauge pressure later, when their temperature has dropped to -40.0ºC?
Physics
1 answer:
kvv77 [185]3 years ago
8 0

Answer: 3.30\times 10^5N/m^2

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

{P_1\times T_1}={P_2\times T_2}

where,

P_1 = initial pressure of gas  = 2.50\times 10^5N/m^2

P_2 = final pressure of gas  = ?

T_1 = initial temperature of gas  = 35^0C=(35+273)K=308K

T_2 = final temperature of gas  =  -40^0C=(-40+273)K=233K

{2.50\times 10^5N/m^2\times 308}={P_2\times 233}

P_2=3.30\times 10^5N/m^2

Therefore, the final gauge pressure in the car tires is 3.30\times 10^5N/m^2

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<em />

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