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Paladinen [302]
3 years ago
11

PLeaSe SoMeBodY HeLp

Physics
1 answer:
Lerok [7]3 years ago
5 0
1). Oört Cloud
2). Kuiper Belt
3). asteroids
4). meteorite

Note: 
Your teacher doesn't need this information ! 
Your teacher needs for you to LEARN stuff.
You have the answers now, but until you memorize the information,
you haven't learned anything.
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An oscillator makes 322.1 oscillations in 4.255 minutes. What is the period of the oscillator?
sergij07 [2.7K]
Ummm I’m not sure let me do the work
4 0
3 years ago
(1) Differentiate EN with respect to r, and then set the resulting expression equal to zero, since the curve of EN versus r is a
Shtirlitz [24]

Answer: The continuation and the last part of the question is  (3) Determine the expression for E0 by substitution of r0 into the above equation for EN. What is the equation that represents the expression for E0?

Explanation:

The detailed steps and appropriate derivation and by differentiation is shown in the attachment.

The knowledge of differential calculus is applied.

5 0
3 years ago
Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist
andreyandreev [35.5K]

Answer:

a) It is moving at 43.15\frac{m}{s^{2}} when reaches the ground.

b) It is moving at 101.44\frac{m}{s^{2}} when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

W=K_f-K_i (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

K=\frac{mv^2}{2} (2)

with m the mass and v the velocity.

Using (2) on (1):

W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

W=Fd=wd=mgd (4)

Using (4) on (3):

mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}

v_f=43.15\frac{m}{s^{2}}

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

-mgd=-\frac{mv_i^2}{2}

Solving for initial velocity (when the boulder left the volcano):

v_i=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*525}

v_i=101.44 \frac{m}{s^{2}}

3 0
3 years ago
What is the average speed of an object with a total distance traveled of 45 meters in 50 seconds
Anettt [7]

Answer: 0.9m/s

Explanation:

Use equation for speed:

V=S/t

S-distance; S=45m

t-time; t=50 s

V=S/t

V=45m/50s

V=0.9 m/s

7 0
4 years ago
An ant moves at 5 cm/s. It takes her 2 minutes to cross a road. How wide is the road?
Alecsey [184]

so as this ant moves

5 cm every second you multiply 5 by 120 (60 per minute as there are 60 seconds in a minute)

this is 600 cm

or

6 meters

4 0
3 years ago
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