On mars people would way less.
An example of this is that if I weighed 700 pounds (I don't by the way) I would then weigh 500 pounds or less.
That's a great idea ! A wind turbine (windmill) or solar panels
on the roof of every WalMart, but don't stop there. Let K-Mart,
Target, Sears, Macy's, 7-11, McDonald's, and Subway in on it too.
In fact, why not place them on the roof of every house and
apartment building too ?
Just one question: Who's going to pay for them ?
_________________________________________________
The biggest single year-round residential use of energy in the
USA is to heat up and keep a ready supply of hot water. So the
single biggest residential use of energy could be eliminated with
a simple solar water heater on the roof of every house. From my
own personal observation, I know that Israel is there now, but here
in the USA, it's apparently not worth the time, effort, or expense ! ? !
Ask ya mother .. she birthed you so she’ll know .
Answer:
D. a nonrenewable resource
Explanation:
From the description given, helium is a non-renewable resource.
- A non-renewable resource is one in which cannot be replenished by natural processes as they consumed.
- They get depleted as they are removed from nature.
- Helium formation cannot match its consumption if exploited.
Answer:
0.345m
Explanation:
Let x (m) be the length that the spring is compress. If we take the point where the spring is compressed as a reference point, then the distance from that point to point where the ball is held is x + 1.1 m.
And so the potential energy of the object at the held point is:
![E_p = mgh](https://tex.z-dn.net/?f=E_p%20%3D%20mgh)
where m = 1.3 kg is the object mass, g = 10m/s2 is the gravitational acceleration and h = x + 1.1 m is the height of the object with respect to the reference point
![E_p = 1.3 * 10 * (x + 1.1) = 13(x + 1.1) = 13x + 14.3 J](https://tex.z-dn.net/?f=E_p%20%3D%201.3%20%2A%2010%20%2A%20%28x%20%2B%201.1%29%20%3D%2013%28x%20%2B%201.1%29%20%3D%2013x%20%2B%2014.3%20J)
According to the conservation law of energy, this potential energy is converted to spring elastic energy once it's compressed
![E_p = E_k = kx^2/2 = 13x + 14.3](https://tex.z-dn.net/?f=E_p%20%3D%20E_k%20%3D%20kx%5E2%2F2%20%3D%2013x%20%2B%2014.3)
where k = 315 is the spring constant and x is the compressed length
![315x^2 = 26x + 28.6](https://tex.z-dn.net/?f=315x%5E2%20%3D%2026x%20%2B%2028.6)
![315x^2 - 26x - 28.6 = 0](https://tex.z-dn.net/?f=315x%5E2%20-%2026x%20-%2028.6%20%3D%200)
![x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
![x = \frac{26 \pm \sqrt{26^2 - 4*(-28.6)*315}}{2*315}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B26%20%5Cpm%20%5Csqrt%7B26%5E2%20-%204%2A%28-28.6%29%2A315%7D%7D%7B2%2A315%7D)
![x = \frac{26 \pm 191.6}{630}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B26%20%5Cpm%20191.6%7D%7B630%7D)
x = 0.345 m or x = -0.263 m
Since x can only be positive we will pick the 0.345m