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Paladinen [302]
2 years ago
11

PLeaSe SoMeBodY HeLp

Physics
1 answer:
Lerok [7]2 years ago
5 0
1). Oört Cloud
2). Kuiper Belt
3). asteroids
4). meteorite

Note: 
Your teacher doesn't need this information ! 
Your teacher needs for you to LEARN stuff.
You have the answers now, but until you memorize the information,
you haven't learned anything.
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A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
iren [92.7K]

Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

3x=(1/2)a(t')^2

Solving for t':

t'=√(6x/a)

Now, the velocity of the motorcycle as a function of time is:

v(t)=a*t

Evaluating at t=t'

v(t')=a*√(6x/a)=√(6*x*a)

Which is the final velocity

Have a nice day!

3 0
3 years ago
According to the law of conservation of mass does the total number of atoms change during aerobic respiration
vichka [17]
NO. although the arrangement of the atoms will change, the total number stays constant.
3 0
2 years ago
A beam of light, initially travelling in the air, strikes water surface at an angle of 24.5° with the normal. If the speed of li
kykrilka [37]

Answer:

Explanation:

n = 3.00e8/2.22e8 = 1.35

1.00sin24.5 = 1.35sinθ

θ = 17.9°

8 0
2 years ago
A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T th
N76 [4]

The mass of the ion is 5.96 X 10⁻²⁵ kg

<u>Explanation:</u>

The electrical energy given to the ion Vq will be changed into kinetic energy \frac{1}{2}mv^2

As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force \frac{mv^2}{r}.

So,

Vq = \frac{1}{2}mv^2

and

Bqv = \frac{mv^2}{r}

Right from these eliminating v, we can derive

m = \frac{B^2r^2q}{2V}

On substituting the value, we get:

m = \frac{(0.4)^2X (0.305)^2 X1.602X 10^-^1^9}{2X 2000}\\\\

m = 5.96 X 10⁻²⁵ kg.

3 0
3 years ago
Suppose that the angular separation of two stars is 0.1 arcseconds, and you photograph them with a telescope that has an angular
Crank

Answer: the photograph will likely show only one star.

Explanation:

Since their angular separation is smaller than the telescope's angular resolution, the picture will apparently show only one star rather than two.

4 0
2 years ago
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