Answer:
1 N
Explanation:
From coulomb's law,
The force of attraction between two charges is inversely proportional to the square of the distance between the charges.
From the question,
Assuming the charges are the same in both case,
F ∝ /r²....................... Equation 1
Fr² = k
F'r'² = Fr²........................... Equation 2
Where F' = First Force, r'² = First distance, F = second force, r² = second distance.
make F the subject of the equation,
F = F'r'²/r².................... Equation 3
Given: F' = 4 N, r' = 3 m, r = 6 m
Substitute into equation 3
F = 4(3²)/6²
F = 36/36
F = 1 N
 
        
             
        
        
        
Answer:
Πr²(4r/3 - h)
Explanation:
Volume of a sphere is 4/3Πr³. If a hole of radius r is bored through, the hole with generate a circular shape in the sphere. The volume of the remaining portion of the sphere will be the difference between the volume of the sphere and the area of the hole bored(which will be volume of a cylinder since the hole bored will create a cylindrical shape in the sphere)
Area of the remaining portion = Volume of sphere - volume of a cylinder 
Volume of sphere = 4/3Πr³
Volume of a cylinder = Πr²h 
Volume of the remaining portion = 4/3Πr³ - Πr²h
= Πr²(4r/3 - h)
Where h is the height of the cylindrical hole
 
        
                    
             
        
        
        
The total potential energy associated with the jumper at the end of his fall is 90,000 J.
The given parameters;
- <em>mass of the jumper, m = 51 kg</em>
- <em>height of the bridge. h  = 321 m</em>
- <em>spring constant of the cord, k = 32 N/m</em>
- <em>extension of the cord, x = 179 m - 104 m = 75 m</em>
The total potential energy associated with the jumper at the end of his fall is calculated as follows;
U = ¹/₂kx² + mgΔh
where;
<em>Δh is the change in height after falling </em>
U = ¹/₂(32)(75)²  + (51)(9.8)(0)
U = 90,000 J
Thus, the total potential energy associated with the jumper at the end of his fall is 90,000 J.
Learn more here:brainly.com/question/15731149
 
        
             
        
        
        
The partial pressure of nitrogen is about 584 mmHg.
        
             
        
        
        
the third answer is right.