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Andru [333]
3 years ago
8

A turbine of a coal burning installation delivers 1,500 hp of mechanical energy to a generator. The generator then converts 80.0

% of the mechanical energy into electrical energy. If the terminal potential difference of the generator is 1560 V, what current does it deliver (in A)?
Physics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

I=573.846\ A

Explanation:

Given:

  • mechanical energy delivered to the generator, E_m=1500\ hp=1119000\ W
  • efficiency of the generator in converting the mechanical energy into electrical, \eta_g=80\%
  • terminal potential difference across the generator output, V=1560\ V

<u>Now the amount of energy converted into electrical energy by the generator:</u>

E_e=E_m\times \eta_g

E_e=1119000\times 80\%

E_e=895200\ W

As power of current is given by:

P=V.I

where:

I= current

Now,

E_e=P

895200=V.I

I=\frac{895200}{1560}

I=573.846\ A

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What is a measure between the difference in start and end positions?
crimeas [40]

Answer:

Displacement

General Formulas and Concepts:

<u>Kinematics</u>

  • Displacement vs Total Distance

Explanation:

Displacement is the difference between the start position and end position.

Total Distance is the entire distance <em>traveled</em> between the start and end position.

Topic: AP Physics 1 Algebra-Based

Unit: Kinematics

5 0
3 years ago
1. A kangaroo hops 84 m to the east in 7 seconds.
DENIUS [597]

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = \frac{distance}{time }   = \frac{84}{7}  = 12m/s

  Velocity  = \frac{displacement}{time}   = \frac{84}{7}   = 12m/s due east

3 0
3 years ago
A 91.0-kg hockey player is skating on ice at 5.50 m/s. another hockey player of equal mass, moving at 8.1 m/s in the
never [62]

The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\rm  m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

8 0
2 years ago
PLSS HELP
trasher [3.6K]

Answer:

Wavelength and Frequency

8 0
3 years ago
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How do I solve for this?
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I can’t see anything
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