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Andru [333]
3 years ago
8

A turbine of a coal burning installation delivers 1,500 hp of mechanical energy to a generator. The generator then converts 80.0

% of the mechanical energy into electrical energy. If the terminal potential difference of the generator is 1560 V, what current does it deliver (in A)?
Physics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

I=573.846\ A

Explanation:

Given:

  • mechanical energy delivered to the generator, E_m=1500\ hp=1119000\ W
  • efficiency of the generator in converting the mechanical energy into electrical, \eta_g=80\%
  • terminal potential difference across the generator output, V=1560\ V

<u>Now the amount of energy converted into electrical energy by the generator:</u>

E_e=E_m\times \eta_g

E_e=1119000\times 80\%

E_e=895200\ W

As power of current is given by:

P=V.I

where:

I= current

Now,

E_e=P

895200=V.I

I=\frac{895200}{1560}

I=573.846\ A

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A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of
jenyasd209 [6]

Answer:

The horizontal component is 37.74 N to east

The vertical component is 16.02 N to North

Explanation:

Any slant vector has two components

→ Horizontal component = R cos Ф

→ Vertical component = R sin Ф

→ R is the magnitude of the vector

→ Ф is the direction of the vector with positive part of the horizontal axis

A slanted vector has a magnitude of 41 N and is at an angle of 23

degrees north of east

23° north of east means the angle between the vector and the

east direction is 23° (east is the positive horizontal direction)

That means R is 41 N and Ф is 23°

→ R = 41 N , Ф = 23°

→ The horizontal component = 41 × cos(23) = 37.74 N east

→ The vertical component = 41 × sin(23) = 16.02 N North

<em>The horizontal component is 37.74 N to east</em>

<em>The vertical component is 16.02 N to North</em>

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A body of mass 20kg initially at rest is subjected to a force of 40m for 15sec. Calculate the change in k.e
Ede4ka [16]

Explanation:

mass(m)=20kg

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now,

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Please help me answer this question
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It can either be all of them or just 1 and 3
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An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the
vovikov84 [41]

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = <u>2</u><u>5</u><u>.</u><u>0</u><u>8</u><u>m</u><u>/</u><u>s</u>

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