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Dafna1 [17]
3 years ago
12

. A car going 50 m/s accelerates to pass a truck. Five seconds later the car is going 80m/s. Calculate the acceleration of the c

ar.
Physics
1 answer:
sineoko [7]3 years ago
8 0
6 mph/s


Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .
You might be interested in
A radio signal takes 1.28 s to travel from a transmitter on the Moon to the surface of Earth. The radio waves travel at 3.00108
yulyashka [42]

Answer:

s = 3.84 x 10⁸ m

Explanation:

The distance traveled by an object, while in uniform motion, is given by the following equation:

s = vt

where,

s = distance covered

v = speed

t = time interval

In this case:

s = distance between Moon and Earth = ?

v = speed of radio waves = 3 x 10⁸ m/s

t = time taken to travel = 1.28 s

Therefore,

s = (3 x 10⁸ m/s)(1.28 s)

<u>s = 3.84 x 10⁸ m</u>

3 0
4 years ago
What is the acceleration of a 31 kg object pushed with a force of 42N
Ray Of Light [21]
I belive it could be 6.5 but I could be wrong
3 0
3 years ago
A football was kicked so that it traveled 65 yards in 3.0 total seconds. What was the speed
Olin [163]

Answer:

vx = 65 yd/3 sec  = 21.7 yd/sec  since horizontal speed is constant

vy = g t = (32 / 3) yd/sec^2 * 1.5 sec = 16 yd/sec   where 32/3 is the acceleration due to gravity in yds / sec^2  and 1.5 is the time to travel each way in the vertical direction

V = (vx^2 + vy^2)^1/2 = (21.7^2 + 16^2)^1/2 = 27 yd/sec

tan theta = vy/vx = 16 / 21.7 = .737    theta = 36.4 deg

You can check using the range formula:

R = v^2 sin (2 theta) / g = 27^2 * .955 / (32 / 3) = 65.3 yds  

The difference from 65 yds may be rounding error.

4 0
4 years ago
In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
USPshnik [31]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
For aerodynamic reasons, nearly all modern aircraft feature at leastone large vertical stabilizer. The B-2 "stealth" bomber pict
andrew-mc [135]

Answer:

Answer:

The reason why the B-2 "stealth" bomber has no vertical fins (or stabilizers) at all, is because by design, the vertical fins are not required to provide stability; the stability for yaw movement is provided through a computer that controls the B-2 stealth bomber; hence the B-2 stealth bomber does not need a vertical stabilizer in order to fly.

6 0
3 years ago
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