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Vsevolod [243]
3 years ago
11

If a rectangle has perimeter of 50 cm., what could its dimensions (length and

Mathematics
2 answers:
Feliz [49]3 years ago
5 0

Answer:

The two middle ones: 15cm and 10cm; 5cm and 20cm

Step-by-step explanation:

The first one would be a rectangle with a perimeter of 100, while the last would have a perimeter of 30.

Vladimir79 [104]3 years ago
3 0

Answer:

Step-by-step explanation:

Given a rectangle where the length is 5cm and the width is 3cm. Find the area of this rectangle.

Solution: To calculate the area, we can use the formula for the area of a rectangle:

A = L×W

Since the length is given as 5cm, we can substitute L with 5. Similarly, since the width is given as 3cm, we can substitute W with 3. After doing so, we can calculate A, as shown below:

A = L×W

A = 3×5

A = 15

Now, the calculated number 15 only has a meaning if we include the unit for it. Since the given length and width are in cm, the unit for area will be cm2. Hence:

A = 15 cm2

Example 2: Find the area of the garden, length and width of the garden are respectively 600m and 400m.

Solution:

Area of garden = Length×Width

A = L×W

A = 600×400

A = 240000 m2

Example 3: A white paper has a size of length 20 cm and width 15 cm. Jack has drawn a rectangle in the center of the paper which is 10 cm in length and 5 cm in width and painted the entire rectangle in violet color. Find the area of the violet colored portion and area of white portion.  

Solution: We know that area of a rectangle is length × width.

Here the given paper has the shape of a rectangle.

So the area of the paper is = 20cm x 15cm = 300cm².

And the area of the violet colored rectangle = 10cm x 5cm = 50cm².

So the area of the white portion = 300cm² - 50cm² = 250cm².

Example 4: The length of a rectangular shaped garden is 250 meters and then the width of the garden is 175 meters. Find the area of the rectangular garden.

Solution: The length of the garden = 250 meter

The width of the garden = 175 meter

Area of the rectangular garden = 250 x 175

                                             = 43,750 m2

Example 5: In an auditorium the floor is covered with a rectangular carpet, which is measured 9 m in length and 6 m in width. Calculate the area of the rectangle carpet.

Solution:

Given that, length (L) of carpet =9m and Breadth of a carpet (W) =6m

Area of rectangle = length Breadth

Area = L × W = 9 × 6 = 54 m2

sorry if it long hope it helps tho

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Answer:

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Learning Task 3:
padilas [110]

Answer:

Area = x^2- 25

Area =9x^2 +24x + 16

Length = (3x -2)

Speed = \left(y^2-3y+1\right)

Product = 3m^3 + 6m^2 - 6m

Step-by-step explanation:

Solving (1):

Length = (x + 5)

Width = (x - 5)

Required

Calculate Area

Area = Length * Width

Area = (x + 5) * (x - 5)

Area = x^2 + 5x - 5x - 25

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Solving (2):

Given

Length = (3x + 4)

Required: Calculate Area

Area =Length * Length

Area =(3x + 4) * (3x + 4)

Area =9x^2 + 12x + 12x + 16

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Solving (3):

Area = 3x^2 + 7x - 6

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Required: Calculate Length

Area = Length * Width

Length = \frac{Area}{Width}

Length = \frac{3x^2 + 7x - 6}{x + 3}

Factorize the numerator

Length = \frac{3x^2 + 9x -2x - 6}{x + 3}

Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}

Length = \frac{(3x -2) (x + 3)}{x + 3}

Divide by x + 3

Length = (3x -2)

Solving (4):

Distance = (2y^3 - 7y^2 + 5y -1)

Time = 2y - 1

Required: Determine the average speed

This is calculated as:

Speed = \frac{Distance}{Time}

Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}

Factorize the numerator

Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}

Speed = \left(y^2-3y+1\right)

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Multiply (m^2 + 2m - 2) by sum of (m + 3) and (2m - 3)

First, calculate the sum:

Sum = m + 3 + 2m - 3

Sum = m +  2m+3 - 3

Sum = 3m

Then, the product

Product = (m^2 + 2m - 2)(3m)

Product = 3m^3 + 6m^2 - 6m

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Step-by-step explanation:

see the attached figure to better understand the problem

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