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AleksAgata [21]
4 years ago
10

Find values of a and b that make the statement |a+b|= |a|+|b| false.

Mathematics
1 answer:
jok3333 [9.3K]4 years ago
3 0

The values that make this statement falser are any in which a and b do not have the same sign.

For instance, if a was equal to 3 and b was equal to -3 than see the results.

|a+b|=

|3+-3|=

|0|= 0

Then see the next equation with the same selections

|a|+|b|

|3|+|-3|

3 + 3 = 6

And this would be true no matter which is the negative, as long as there is one negative and one positive.

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Write an equation of a line containing (2, -3) and perpendicular to 3x+4y=14 answer
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Answer:

Step-by-step explanation:

From the condition of perpendicularity, if two lines must be perpendicular to each other, the product of their gradient rather the slope must be equaled to ( -1 ).

Equation of a line ; y = mx+ c, where m1 is the gradient of the line and c us the point of intersection if the line on the y- axis.therefore, the equation

3x + 4y = 14, when re arranged, now becomes, 4y = -3x + 14, divide through by 4, gives, y = -3x/4 + 14.

Therefore, m1, = -3/4 and m2, = 4/3 going by the condition. Since the line passes through the coordinate of (2,3), where x = 2, and y = -3, then, substitute for x and y in y = mx+ c, minding the m2, to find C, therefore,

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3y = -4x - 17.

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