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Tju [1.3M]
3 years ago
15

Hi can you help me with this thingy about slopey slope? thanks

Mathematics
2 answers:
Bond [772]3 years ago
3 0
Gavin earns more because he earns 20 per hour and eva earns 11.5 per hour.

So Gavin earns 8.50 more than eva.

Hope this helps :)
kirill [66]3 years ago
3 0
As we see in the graph Gavin earns 20$ per hour and Eva earns 23$ every two hours.

First, we must figure out how much Eva made in an hour
23 ÷ 2hours = 11.5

Now we subtract to find the difference
20$ (Gavins) - 11.5$ (Evas) = 8.50
Gavins by $8.50 is your answer

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The first equation from the previous system of
Lunna [17]

Answer:

(3,-2)

Step-by-step explanation:

4 0
3 years ago
What is the straight-line distance between (2, -4) and (-3, 8) on a coordinate grid?
Scrat [10]
It is most likely 14 units so it would be A. I think.
6 0
2 years ago
I need help finding this answer because I am pretty sure it’s C but I don’t know
malfutka [58]

Answer: A) -9

Step-by-step explanation:

If x = -2

Then 3^{x} = 3^{-2}

So, it is -9

5 0
2 years ago
What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
Travka [436]
The standard equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

where the center is at point (h,k)

From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be

r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241

Thus, the equation of the circle is

(x-2)^{2} + (y+5)^{2} =241
4 0
2 years ago
PLEASE HELP ASAP!!!!
Setler [38]

Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.

To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.

Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.

Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.

Therefore:

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 8}  \\ f(4) = 3 \end{cases}}

The nth root of a can contain negative number only if n is an odd number.

\large{  \begin{cases} f( - 8 ) =   \sqrt[3]{ - 2 \times -  2 \times   - 2}  \\ f(4) = 3 \end{cases}} \\  \large{  \begin{cases} f( - 8 ) =  - 2\\ f(4) = 3 \end{cases}}

Answer

  • f(-8) = -2
  • f(4) = 3
6 0
2 years ago
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