A sweater is marked down from 25 to 19 what is the percent of change
2 answers:
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Answer:
D. 3
Step-by-step explanation:
Assuming the model represents an equation, the following can be deduced:
On the left side of the equation, the model shows we have 3 "x's", and 6 "1's". Let this represent:
3x + 6
On the right side of the equation, we have 2 "x's" and 9 "1's". Let this represent:
2x + 9.
The model would represent the equation below:
Solve for x
(Subtracting 2x from both sides of the equation)
(subtracting 6 from both sides of the equation)
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W =
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards