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pashok25 [27]
3 years ago
8

Each joule is one ____. newton of energy gram of energy meter of energy newton·meter of energy

Chemistry
1 answer:
bezimeni [28]3 years ago
5 0
Joule is a unit of work or energy. Work is calculated by multiplying the amount of force exerted with the displacement of the object. The equation would then be,
                               W = F x d
If we are to write the units of measurement for the given parameters, that would be
                       Joules = Newton x meter
Thus, the answer is newton.meter of energy. The answer is the last choice. 
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In a titration, 4.7 g of an acid (HX) requires 32.6 mL of 0.54 M NaOH(aq) for complete reaction. What is the molar mass of the a
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Answer : The molar mass of an acid is 266.985 g/mole

Explanation : Given,

Mass of an acid (HX) = 4.7 g

Volume of NaOH = 32.6 ml = 0.0326 L

Molarity of NaOH = 0.54 M = 0.54 mole/L

First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

\text{Moles of an acid}=\frac{\text{Mass of an acid}}{\text{Molar mass of an acid}}

Now put all the given values in this formula, we get:

0.017604mole=\frac{4.7g}{\text{Molar mass of an acid}}

\text{Molar mass of an acid}=266.985g/mole

Therefore, the molar mass of an acid is 266.985 g/mole

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When positively charged particles were radiated onto a gold atom, a few of the particles bounced back. Which of the following ca
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Plastic is used to cover the copper wire in the power codes of appliances because plastic differs from copper in _________. 1. D
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Explanation:

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How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

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C2= 0.20

V2= ?

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V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

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