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2 years ago

Mention 3 types of making bases

Chemistry

2 answers:

Setler79 [48]2 years ago

8 0

Answer:

Preparation of Bases

By the direct union of a metal with oxygen Some metals when heated in air or oxygen form the oxides of the metals. ... By the action of water or steam on some active metals Some active metals like sodium and potassium react with cold water to form hydroxides with the evolution of hydrogen gas.

Pavlova-9 [17]2 years ago

3 0

On the basis of acidity bases can be classified into three types: monoacidic, diacidic and triacidic.
Sodium hydroxide: NaOH
Potassium hydroxide: KOH
Calcium hydroxide: Ca(OH); 2
Rubidium hydroxide: RbOH

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Answer: b

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2 years ago

Use bond energies to determine δhrxn for the reaction between ethane and chlorine. ch3ch3(g)+cl2(g)→ch3ch2cl(g)+hcl(g)

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For this reaction to proceed, the following bond breaking should occur:

*one C-H bond
* one Cl-Cl bond

After, the following bond formations should occur:
*one C-Cl bond
*one H-Cl bond

Now, add the bond energies for the respective bond energies which can be found in the attached picture. For bond formations, energy is negative. For bond breaking, energy is positive.

ΔHrxn = (1)(413) + (1)(242) + 1(-328) + 1(-431) = -104 kJ

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3 years ago

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when the equation __ cu __h2so4 → __cuso4 __h2o __so2 is correctly balanced, what is the coefficient of cuso4?

schepotkina [342]

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7 0

3 years ago

Be sure to answer all parts. ΔH o f of hydrogen chloride [HCl(g)] is −92.3 kJ/mol. Given the following data, determine the ident

goldenfox [79]

Answer:

NH₄Cl(s) → NH₃(g) + HCl(g)

ΔH°rxn 74,89 kJ/mol

Explanation:

The change in enthalpy of formation (ΔHf) is defined as the change in enthalpy in the formation of a substance from its constituent elements. For HCl(g):

(1) ¹/₂H₂(g) + ¹/₂ Cl₂ → HCl(g) ΔH = -92,3 kJ/mol

It is possible to sum ΔH of different reactions to obtain ΔH of a global reaction (Hess's law).

For the reactions:

(2) N₂(g) + 4H₂(g) + Cl₂(g) → 2NH₄Cl(s) ΔH°rxn = −630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

The sum of -(2) + (3) gives:

-(2) 2NH₄Cl(s) → N₂(g) + 4H₂(g) + Cl₂(g) ΔH°rxn = +630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

-(2) + (3) 2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g)

ΔH°rxn = +630.78 kJ/mol −296.4 kJ/mol = +334,38 kJ/mol

Now, the sum of -(2) + (3) + 2×(1)

-(2) + (3) 2NH₄Cl(s) → 2NH₃(g) + H₂(g) + Cl₂(g) ΔH°rxn = +334,38 kJ/mol

2×(1) H₂(g) + Cl₂(g)→ 2HCl(g) ΔH = 2×-92,3 kJ/mol

-(2) + (3) + 2×(1) 2NH₄Cl(s) → 2NH₃(g) + 2HCl(g)

ΔH°rxn = +334,38 kJ/mol + 2×-92,3 kJ/mol = 149,78 kJ/mol

The reaction of:

NH₄Cl(s) → NH₃(g) + HCl(g)

Has ΔH°rxn = 149,78kJ/mol / 2 = 74,89 kJ/mol

I hope it helps!

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3 years ago

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enot [183]

Answer: The crystal structure of ionic compounds is strong and rigid. It takes a lot of energy to break all those ionic bonds. As a result, ionic compounds are solids with high melting and boiling points.

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3 years ago

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Mention 3 types of making bases​

Mention 3 types of making bases