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pickupchik [31]
3 years ago
9

Chico by 75 shares of stock at $19.58 per share he receives dividends of $73.42 during the year at the end of the year his stock

is valued at $22.14 what was his value at the end of the year
Mathematics
1 answer:
Brut [27]3 years ago
7 0

Answer: 192

Step-by-step explanation:

(22.14-19.58)x75

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You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until y
Luba_88 [7]
Current amount in account
P=36948.61

Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n

Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11

We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000

We can solve this by trial and error.


The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000.  It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.

So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.

So it takes 15.00 years to reach the goal of 280000 years.
8 0
3 years ago
the price of a gallon of unleaded gas was $2.86 yesterday. today, the price fell to $2.79. find the percent decrease. round answ
soldier1979 [14.2K]
So.. 2.86 - 2.79 is the amount in decrease or 0.07

so.. if we take 2.86 as the 100%, how much is 0.07 of that in percentage?

well \bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
2.86&100\\
0.07&x
\end{array}\implies \cfrac{2.86}{0.07}=\cfrac{100}{x}

solve for "x"
3 0
3 years ago
9-12r>-99 and -2r-4<-12
Umnica [9.8K]
Hello there!

9 - 12r > -99
-12r > -108
r \leq 9 is your first inequality.

-2r - 4 < -12
-2r < -8
r \geq 4 is your second inequality.

I hope this helps!
3 0
3 years ago
a church youth group has 246 people. one-third ride cars to the fair. the rest ride a bus. how many ride the bus?
Lena [83]
82 take a car, 164 take bus
3 0
3 years ago
Read 2 more answers
Ethan and Emily went shopping at a local farmers’ market. They both bought the same type of apples and potatoes at the same stan
Effectus [21]
<h3>Ordered pair representing the price per pound of apples, x, and potatoes, y is (2.5, 1.1).</h3>

Step-by-step explanation:

Let us assume that the cost of per pound of apples  = $ x

Assume that the cost of per pound of potatoes  = $ y

Now, according to question:

The cost of  8 pounds of apples and 5 pounds of potatoes  = $25.50

⇒ Cost of 8 pounds of Apple +   Cost of 5 pounds of potatoes  =  $25.50

⇒ 8 x (Cost of 1 pound apple)  +  5 x ( cost of  1 pound potato )  = $25.50

⇒ 8 x + 5 y =  $25.50  .... (1)

⇒  5 y =  25.5 - 8 x

Similarly,

The cost of 3 pounds of apples and 10 pounds of potatoes = $18.50

⇒ 3 x + 10 y =  $18.50  .... (2)

or,   1.5 x +5 y =  $ 9.25   ( dividing the equation by 2)  

⇒ 5 y =  9.25  - 1.5 x

Now, comparing both equations,we get:

25.5 - 8 x = 9.25  - 1.5 x

⇒ 25.5 - 9.25 =  8 x - 1.5 x

⇒ 16.25 =  6.5 x

⇒ x = 2.5

Putting this value of x in   5 y =  9.25  - 1.5 x, we get:

5 y  = 9.25 - 1.5 (2.5)

⇒ 5 y =  5.5

⇒ y = 1.1

So, the cost of 1 pound of apples  = $2.5

The cost pf 1 pound of potatoes = $1.1

The ordered pair (x,y) is given as : (x,y)  = (2.5,1.1)

3 0
3 years ago
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