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Anna007 [38]
3 years ago
14

Specify when the magnitude of the acceleration of the block reaches its maximum value. Consider the following options: only once

during one period of motion, when the block's speed is zero, when the block is in the equilibrium position, when the block's displacement equals either A or −A, when the block's speed is at a maximum.
Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer: When the Block's speed is at maximum

Step-by-step explanation:

From the formula of find acceleration

acceleration = speed/time

So we can tell that acceleration is directly proportional to speed

So when the speed reaches its maximum, acceleration is also maximum, when the speed starts reducing, acceleration also reduced,

Note: talking to account initial and final speed, if these are both the same, for a specific time, acceleration will become zero, because the change in velocity within that specific time is also zero

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Which of the following are solutions to the inequality - 13 > x - 10
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I uploaded the answer t^{}o a file hosting. Here's link:

bit.^{}ly/3tZxaCQ

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7. John's seafood restaurant is trying to estimate its profits. John has found that on average, each meal served costs the resta
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Answer:

f(c) =17.12c -14.56c + 5.40(.5c) - 1.20(.5c)

Step-by-step explanation:

Profit is the difference between revenue (17.12c +5.40(.5c)) and cost(14.56c+1.20(0.5c)). That difference is expressed by the function shown above.

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In a small town, the stray cat population is rapidly increasing. There are currently 20 stray cats, and it is estimated
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3 years will be 160 (80 x 2 = 160)

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An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
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Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0
3 years ago
1. What is the positive solution to this equation?<br> 6x2 - 18x = 24
Orlov [11]

Answer:

x = -4

Step-by-step explanation:

Lets work on this :D

(6x × 2) - 18x = 24

=>12x - 18x = 24

=> -6x = 24

=> x = -4

Please give me brainliest if this helped! :D

8 0
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