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4 years ago

7

Which of the following points lies on the circle whose center is at the origin and whose radius is 10?

1 answer:

Naddik [55]4 years ago

6 0

Since the standard form of the circle is:

(x-h)^2+(y-k)^2=r^2, and (h,k)=(0,0) and r=10 so we have:

x^2+y^2=100 Looking at the points you have:

(√10, 0) does not work as (√10)^2+0^2=10+0=10

(0, 2√5) does not work as 0^2+(2√5)^2=0+20=20

(5√2, 5√2) works as (5√2)^2+(5√2)^2=50+50=100

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(4x - 5)^x - 19 = ×=3

anastassius [24]

It is (12-5)^3-19=324

5 0

3 years ago

Which expression is equal to the example?

Aloiza [94]

$1-(cosx)^4$ value is $2sin^4-sin^4x$ . Correct option is D) $2sin^4-sin^4x$ .

<u>Step-by-step explanation:</u>

Here we have , expression to evaluate:

$1-(cosx)^4$

⇒ $1-((cosx)^2)^2$

⇒ $1-(1-(sinx)^2)^2$

We know that , $sin^2x = 1-cos^2x$ , putting value in equation $1-(1-(sinx)^2)^2$

⇒ $1-(1+sin^4x-2sin^4)$

⇒ $1-1-sin^4x+2sin^4$

⇒ $-sin^4x+2sin^4$

⇒ $2sin^4-sin^4x$

Therefore , $1-(cosx)^4$ value is $2sin^4-sin^4x$ . Correct option is D) $2sin^4-sin^4x$

4 0

3 years ago

24 - 4 x 2 + 4b = 20 - 16

AnnZ [28]

Answer:

b = -3

Step-by-step explanation:

Solve for b:

4 b - 4 2 + 24 = 20 - 16

-4×2 = -8:

4 b + -8 + 24 = 20 - 16

Grouping like terms, 4 b - 8 + 24 = 4 b + (24 - 8):

4 b + (24 - 8) = 20 - 16

24 - 8 = 16:

4 b + 16 = 20 - 16

20 - 16 = 4:

4 b + 16 = 4

Subtract 16 from both sides:

4 b + (16 - 16) = 4 - 16

16 - 16 = 0:

4 b = 4 - 16

4 - 16 = -12:

4 b = -12

Divide both sides of 4 b = -12 by 4:

(4 b)/4 = (-12)/4

4/4 = 1:

b = (-12)/4

The gcd of -12 and 4 is 4, so (-12)/4 = (4 (-3))/(4×1) = 4/4×-3 = -3:

Answer: b = -3

4 0

4 years ago

P= $16,000, r= 10%, t= 180 days<br> Assume 360 days in a year.

labwork [276]

Interest = (principal)(rate as a decimal)(time in years)

I = (16,000)(0.1)(0.5)
I = $800

3 0

3 years ago

Read 2 more answers

Please help needs turned in

Alecsey [184]

When you have

$4x=\dfrac{2}{5}$

you can solve the equation by multiplying both sides by 1/4. Then simplify.

$4x\cdot\dfrac{1}{4}=\dfrac{2}{5}\cdot\dfrac{1}{4}\\\\x\cdot\dfrac{4}{4}=\dfrac{2\cdot 1}{5\cdot 4}\\\\x=\dfrac{2}{20}=\dfrac{1}{10}$

4 0

3 years ago