Answer:
C?
Explanation:
My best guess would be C as it's the only answer that gives a reason behind the statement.
Answer:
14 m/s²
Explanation:
Start with Newton's 2nd law: Fnet=ma, with F being force, m being mass, and a being acceleration. The applied forces on the left and right side of the block are equivalent, so they cancel out and are negligible. That way, you only have to worry about the y direction. Don't forget the force that gravity has the object. It appears to me that the object is falling, so there would be an additional force from going down from weight of the object. Weight is gravity (can be rounded to 10) x mass. Substitute 4N+weight in for Fnet and 1kg in for m.
(4N + 10 x 1kg)=(1kg)a
14/1=14, so the acceleration is 14 m/s²
Answer:
(a). The average daily demand of this subdivision is 2444.44 gallon/min.
(b). The design-demand used to design the distribution system is 2444.44 gallon/min.
Explanation:
Given that,
Area = 1100 acres
Number of house in 1 acres = 4


Per house water demand = 800 g/day/house
(a). We need to calculate the average daily demand of this subdivision
Using formula for average daily demand





The average daily demand of this subdivision is 2444.44 gallon/min.
(b). We need to calculate the design-demand used to design the distribution system
Using formula for the design-demand



Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.
(b). The design-demand used to design the distribution system is 2444.44 gallon/min.
Answer:
The velocity at the top of its path will be zero (0)
Explanation:
We can solve this problem or particular situation using the principle of energy conservation.
Which tells us that energy is transformed from kinetic energy to potential energy and vice versa. A reference point should be considered at which the potential energy is zero, and at this point the initial velocity of 40 [m/s] is printed to the ball.
![Ek=Ep\\where:\\Ek=kinetic energy [J]\\Ep=potencial energy [J]](https://tex.z-dn.net/?f=Ek%3DEp%5C%5Cwhere%3A%5C%5CEk%3Dkinetic%20energy%20%5BJ%5D%5C%5CEp%3Dpotencial%20energy%20%5BJ%5D)
The potential energy is determined by:
![Ep=m*g*h\\where:\\m=mass of the ball[kg}\\g=gravity[m/s^2]\\h=heigth [m]\\](https://tex.z-dn.net/?f=Ep%3Dm%2Ag%2Ah%5C%5Cwhere%3A%5C%5Cm%3Dmass%20of%20the%20ball%5Bkg%7D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Dheigth%20%5Bm%5D%5C%5C)
The kinetic energy is determined by:
![Ek=\frac{1}{2}*m*v_{0} ^{2} \\where\\v_{0} = initial velocity[m/s]](https://tex.z-dn.net/?f=Ek%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_%7B0%7D%20%5E%7B2%7D%20%20%5C%5Cwhere%5C%5Cv_%7B0%7D%20%3D%20initial%20velocity%5Bm%2Fs%5D)
![Ek=Ep\\\frac{1}{2} *m*v_{0} ^{2} =m*9.81*h\\h=\frac{40^{2}}{2*9.81} \\h=81.5[m]](https://tex.z-dn.net/?f=Ek%3DEp%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av_%7B0%7D%20%5E%7B2%7D%20%3Dm%2A9.81%2Ah%5C%5Ch%3D%5Cfrac%7B40%5E%7B2%7D%7D%7B2%2A9.81%7D%20%5C%5Ch%3D81.5%5Bm%5D)
This will be the maximum path but, its velocity at this point will be zero. Because now all the kinetic energy has been transformed in potential energy.