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TEA [102]
3 years ago
5

A bicyclist rides forward with a positive acceleration. How would her acceleration be different if she had less mass?

Physics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

increase

Explanation:

According to the Newtons second law

F = m a

Where, m be the mass of the object, a be the acceleration of the body

Rider applies the same force so the acceleration depends on the mass.

As mass is less so acceleration is more as acceleration is inversely proportional to the amass of body.

Angelina_Jolie [31]3 years ago
6 0
Her acceleration would increase, if mass decreases than the acceleration would increase
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Troposphere, stratosphere, mesosphere, thermosphere, exosphere
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3 years ago
1. While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his mo
Elenna [48]

1350kgm/s

Explanation:

Given parameters:

Mass of Sam = 75kg

Velocity = 18m/s

Unknown:

Momentum = ?

Solution:

Momentum is the property of a moving body with respect to its mass and velocity.

Objects in motion have momentum. The more the velocity of a body, the more its momentum. Also, the more the mass of an object, the more momentum it possess.

Momentum is a function of the mass and the velocity of a body

   Momentum = mass x velocity

   Momentum = 75 x 18 = 1350kgm/s

learn more:

Conservation of momentum brainly.com/question/2990238

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5 0
3 years ago
Read 2 more answers
Perform the following calculations and give your answer with the correct number of significant figures
love history [14]

Answer:

see below

Explanation:

a. 0.1886 x 12 =2.2632

This has 2 sig figures so the answer can only have 2 sig figures

2.3

b. 2.995 - 0.16685 =2.82815

The most accurate in the problem is to thousands place so our answer can only be accurate to the thousands place

2.828

c. 910 x 0.18945=172.3995

The  least number of significant figures is 3 so the answer can only have 3 significant figures

172

3 0
3 years ago
A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc
hoa [83]

Answer:

option E

Explanation:

given,

diameter = 4 mm

shutter speed = 1/1000 s

diameter of aperture = ?

shutter speed = 1/250 s

exposure time to the shutter time

E V = log_2(\dfrac{N^2}{t})

N is the diameter of the aperture and t is the time of exposure

now,

log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})

\dfrac{N_1^2}{t_1}=\dfrac{N_2^2}{t_2}

inserting all the values

\dfrac{4^2}{1000}=\dfrac{N_2^2}{250}

      N₂² = 4

      N₂ = 2 mm

hence , the correct answer is option E

4 0
3 years ago
A slit of width 2.0 μm is used in a single slit experiment with light of wavelength 650 nm. If the intensity at the central maxi
Valentin [98]

Answer:

The intensity at 10° from the center is 3.06 × 10⁻⁴I₀

Explanation:

The intensity of light I = I₀(sinα/α)² where α = πasinθ/λ

I₀ = maximum intensity of light

a = slit width = 2.0 μm = 2.0 × 10⁻⁶ m

θ = angle at intensity point = 10°

λ = wavelength of light = 650 nm = 650 × 10⁻⁹ m

α = πasinθ/λ

= π(2.0 × 10⁻⁶ m)sin10°/650 × 10⁻⁹ m

= 1.0911/650 × 10³

= 0.001679 × 10³

= 1.679

Now, the intensity I is

I = I₀(sinα/α)²

= I₀(sin1.679/1.679)²

= I₀(0.0293/1.679)²

= 0.0175²I₀

= 0.0003063I₀

= 3.06 × 10⁻⁴I₀

So, the intensity at 10° from the center is 3.06 × 10⁻⁴I₀

5 0
3 years ago
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