Answer:
F = 50636.873 N
Explanation:
given,
bucket of water = 700-kg
length of cable = 20 m
Speed = 40 m/s
angle of the cable = 38.0°
let air resistance be = F
tension in rope be = T
T cos 38° = m×g..................(1)
..........(2)
equation (1)/(2)


F = 50636.873 N
Hence the force exerted on the bucket is equal to F = 50636.873 N
In spring mass system we know that angular frequency is given as

f = 8.38 Hz


now we know that speed of SHM at its extreme position is given by

here we know that
A = 17.5 cm


so maximum speed is 9.21 m/s
Force = (mass) x (acceleration) Newton's second law of motion.
Force = (2 kg) x (3 m/s²) = 6 newtons.
Mohs hardness scale. hope this helps