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professor190 [17]
3 years ago
8

What noise does hydrogen gas make when ignited

Chemistry
2 answers:
malfutka [58]3 years ago
8 0
If you mean,a test test tube,when you collect it using some filtering or something.
Basically,Science class.Hydrogen,is a minor of explosion,100 times the amount of
gas.Your welcome,<em />I'm <em>Roxaroo!!!!!!!!!!!!!

</em>
sveta [45]3 years ago
5 0
It makes a sequeeky kind pop noise we did and experiment on da so yh.
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Find the final product for: Li + Br and show work.
miskamm [114]

Lithium is atomic number 3, so it has valency 1

While, Bromine is atomic number 35, and has valency 1

Lithium has an extra electron while Bromine need an electron, since they both need and have one electron, the form

LiBr (Lithium Bromide) where Li is +ve charged and Br is -ve charged

Happy to help :)

7 0
3 years ago
What equipment might you use to find the SHC of a material? Need to know the answer ASAP PLZ
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3 years ago
Suppose you are titrating an acid solution with a base solution of known concentration. To calculate the concentration of the ac
Arturiano [62]

Answer:

i would say use 2

Explanation:

4 0
3 years ago
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
Why does ice float on water?
Anni [7]
Ice is less dese than water
5 0
3 years ago
Read 2 more answers
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