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3 years ago

What noise does hydrogen gas make when ignited

2 answers:

8 0

If you mean,a test test tube,when you collect it using some filtering or something.
Basically,Science class.Hydrogen,is a minor of explosion,100 times the amount of
gas.Your welcome,<em />I'm <em>Roxaroo!!!!!!!!!!!!!

</em>

sveta [45]3 years ago

5 0

It makes a sequeeky kind pop noise we did and experiment on da so yh.

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Based on molecular orbital theory, the bond orders of the H—H bonds in H 2 , H 2 + , and H 2 - are _________, respectively

vodka [1.7K]

Answer:

H2-1

H2+-1/2

H22- zero

Explanation:

Bond order= Bonding electrons-antibonding electrons/2

In H2, there are two bonding electrons and no antibonding electrons. In H2+ there is only one bonding electron and no antibonding electron while in H22- there are two bonding and two antibonding electrons respectively.

4 0

3 years ago

WILL GIVE BRAINLIEST!!!

Alchen [17]

Answer:

19.20 g. Explanation: ∵ mass % = [mass of solute/mass of solution] x 100

8 0

2 years ago

Jenna notices that the speed of the wind has increased throughout the day. What is causing the faster wind?

Cloud [144]

Answer:

i think the answer is the difference in air pressure has decreased because

Explanation:

The wind is caused by differences in atmospheric pressure. When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds. On a rotating planet, air will also be deflected by the Coriolis effect, except exactly on the equator.

5 0

3 years ago

Read 2 more answers

In a chemical reaction 18 grams of hydrochloride acid reacts with 20 grams of sodium hydroxine to produce sodium chlorine and wa

masya89 [10]

Answer:

The mass of water formed is 38 grams

Explanation:

6 0

2 years ago

How much heat to change 1 mole of ice at -25 °C to steam at +125 °C? • heat to warm ice - heat to melt ice (no temperature chang

Ahat [919]

Answer : The amount of heat changes is, 56.463 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-25^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(125^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat changes = ?

n = number of moles of water = 1 mole

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

m = mass of water

$\text{Mass of water}=\text{Moles of water}\times \text{Molar mass of water}=1mole\times 18g/mole=18g$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[18g\times 4.18J/gK\times (0-(-25))^oC]+1mole\times 6010J/mole+[18g\times 2.09J/gK\times (100-0)^oC]+1mole\times 40670J/mole+[18g\times 1.84J/gK\times (125-100)^oC]$

$\Delta H=56463J=56.463KJ$ (1 KJ = 1000 J)

Therefore, the amount of heat changes is, 56.463 KJ

8 0

3 years ago