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Lina20 [59]
3 years ago
7

Its on the pic so plz look

Chemistry
2 answers:
Naya [18.7K]3 years ago
7 0
The answer is Subscript
Gre4nikov [31]3 years ago
3 0

Answer:

Subscript

Explanation:

Hope this helps

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When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ
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When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
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1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
        
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∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025=  0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
 = 0.0075 * 63.546 =0.477 g


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