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Lina20 [59]
3 years ago
7

Its on the pic so plz look

Chemistry
2 answers:
Naya [18.7K]3 years ago
7 0
The answer is Subscript
Gre4nikov [31]3 years ago
3 0

Answer:

Subscript

Explanation:

Hope this helps

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How to determine Km and Vm from a graph
ElenaW [278]

Answer:

From the graph find the maximum velocity and half it i.e. Vmax/2. Draw a horizontal line from this point till you find the point on the graph that corresponds to it and read off the substrate concentration at that point. This will give the value of Km.

5 0
2 years ago
A 3.00-kg block of copper at 23.0°C is dropped into a large vessel of liquid nitrogen at 77.3 K. How many kilograms of nitrogen
hammer [34]

Answer:

1.2584kg of nitrogen boils.

Explanation:

Consider the energy balance for the overall process. There are not heat or work fluxes to the system, so the total energy keeps the same.

For the explanation, the 1 and 2 subscripts will mean initial and final state, and C and N2 superscripts will mean copper and nitrogen respectively; also, liq and vap will mean liquid and vapor phase respectively.

The overall energy balance for the whole system is:

U_1=U_2

The state 1 is just composed by two phases, the solid copper and the liquid nitrogen, so: U_1=U_1^C+U_1^{N_2}

The state 2 is, by the other hand, composed by three phases, solid copper, liquid nitrogen and vapor nitrogen, so:

U_2=U_2^C+U_{2,liq}^{N_2}+U_{2,vap}^{N_2}

So, the overall energy balance is:

U_1^C+U_1^{N_2}=U_2^C+U_{2,liq}^{N_2}+U_{2,vap}^{N_2}

Reorganizing,

U_1^C-U_2^C=U_{2,liq}^{N_2}+U_{2,vap}^{N_2}-U_1^{N_2}

The left part of the equation can be written in terms of the copper Cp because for solids and liquids Cp≅Cv. The right part of the equation is written in terms of masses and specific internal energy:

m_C*Cp*(T_1^C-T_2^C)=m_{2,liq}^{N_2}u_{2,liq}^{N_2}+m_{2,vap}^{N_2}u_{2,vap}^{N_2}-m_1^{N_2}u_1^{N_2}

Take in mind that, for the mass balance for nitrogen, m_1^{N_2}=m_{2,liq}^{N_2}+m_{2,vap}^{N_2},

So, let's replace m_1^{N_2} in the energy balance:

m_C*Cp*(T_1^C-T_2^C)=m_{2,liq}^{N_2}u_{2,liq}^{N_2}+m_{2,vap}^{N_2}u_{2,vap}^{N_2}-m_{2,liq}^{N_2}u_1^{N_2}-m_{2,vap}^{N_2}u_1^{N_2}

So, as you can see, the term m_{2,liq}^{N_2}u_{2,liq}^{N_2} disappear because u_{2,liq}^{N_2}=u_{1,liq}^{N_2} (The specific energy in the liquid is the same because the temperature does not change).

m_C*Cp*(T_1^C-T_2^C)=m_{2,vap}^{N_2}u_{2,vap}^{N_2}-m_{2,vap}^{N_2}u_1^{N_2}

m_C*Cp*(T_1^C-T_2^C)=m_{2,vap}^{N_2}(u_{2,vap}^{N_2}-u_1^{N_2})

The difference (u_{2,vap}^{N_2}-u_1^{N_2}) is the latent heat of vaporization because is the specific energy difference between the vapor and the liquid phases, so:

m_{2,vap}^{N_2}=\frac{m_C*Cp*(T_1^C-T_2^C)}{(u_{2,vap}^{N_2}-u_1^{N_2})}

m_{2,vap}^{N_2}=\frac{3kg*0.092\frac{cal}{gC} *(296.15K-77.3K)}{48.0\frac{cal}{g}}\\m_{2,vap}^{N_2}=1.2584kg

3 0
3 years ago
0.44 mL/min to microliters per second
SashulF [63]

Answer:

7 μl /s

Explanation:

Given data:

0.44 mL/min

μl /s = ?

Solution:

First of all we will convert the mL/min to mL/s.

we will divide the given value by 60.

0.44/60

0.007 mL/s

Now we will convert the mL/s to μl /s.

we will multiply the value with 1000.

0.007 × 1000

7 μl /s

7 0
3 years ago
HELP PLEASEE ITS ALREADY PAST DUE I NEED THIS
FromTheMoon [43]

i think its b because yeah

5 0
3 years ago
Read 2 more answers
What is the covalent<br> bonding of calcium chloride​
algol13

Answer:

<u>Calcium chloride does not have a covalent bond , it is an ionic bond (which means donation of electrons takes place )</u>. The charge of calcium ions is +2, while the charge of sodium ions is -1. The molecule of calcium chloride contains one calcium ion (+2) and two chloride ions (-1), resulting in an overall charge of 0, or neutral.

<u>IONIC BONDING IN CALCIUM CHLORIDE</u> (CaCl_2)

Electron sharing produces covalent compounds, while electron donation produces ionic compounds. CaCl_2 is a salt with an ionic bond. This is because calcium takes up an electron to each of the chlorine atoms, resulting in Ca^2^+ions for calcium andCl^- ions for chlorine. At room temperature, it behaves like a normal ionic halide and is solid. Calcium is a metal with a non-metal sulphate bond.

<u>Thus , Calcium chloride have ionic bonds present on them . No covalent bonds takes place in calcium chloride.</u>

5 0
3 years ago
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