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Soloha48 [4]
3 years ago
7

In which material are the particles arranged in a regular geometric pattern?

Chemistry
2 answers:
Stella [2.4K]3 years ago
7 0

Answer: 4, C12 H22 O11

Explanation:

"regular geometric" means you're looking at a solid. In a molecular gas, you will have a particular shape, but it's randomly oriented and there's no "regularity" to its placment. Similarly with the molecular liquid. The aq salt is even worse -- the molecules no longer even have a geometric shape.

A regular geometric pattern (crystal) has to be the solid. You don't really need to know what pattern it forms, since the other three answers can't be the answer.Table sugar forms cubes as a solid, where the molecules are arranged in neat rows.

brilliants [131]3 years ago
5 0
Answer=4

Only solids can create regular geometric patterns... CO2 is a gas, H2O is a liquid and Sodium Chloride doesn't count because it's dissolved in a solution...
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Does a physical change form a new substance
beks73 [17]

Answer:

No. No new substance is formed during Physical change.

4 0
3 years ago
How do we find the number of electrons in an atom?
Anon25 [30]

I Believe this is the right answer:

Get a periodic table of elements. ...

Find your element on the periodic table. ...

Locate the element's atomic number. ...

Determine the number of electrons. ...

Look for the atomic mass of the element. ...

Subtract the atomic number from the atomic mass.

Hoped this helped!

5 0
3 years ago
Many grams of aluminum are required to produce 3.5 moles Al2O3 in the presence of excess O2?
Aleks [24]
The  grams  of aluminum  that are required   to produce  3.5  moles of AlO3  in  presence of excess O2   is calculated as  below

write  the  equation for reaction
4 Al + 3O2 =2 Al2O3

by use of mole  ratio between  Al  to  Al2O3   which  is  4 :2  the moles of  Al 
=3.5 x4/2 = 7  moles

mass of Al  =  moles /   x molar mass

= 7 moles  x27 g/mol  =189  grams

4 0
3 years ago
The reducing agent in this catalytic hydrogenation reaction was molecular hydrogen (H2), which was produced in situ (in the reac
creativ13 [48]

Answer:

a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7} c) No H_{2} was not the limiting reactant.

Explanation:

Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.

a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.

b)  4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7}

c) H_{2} was not the limiting reactant based on the mol to mol ratio of H_{2} and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of H_{2} would also be produced.

4 0
3 years ago
In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc
natita [175]

Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water 

x= 0.7535 g water




3 0
3 years ago
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