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alexandr402 [8]
3 years ago
8

When hno2 dissociates in water, which atom is dontaing electrons, allowing water to act as a lewis base?

Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0

Answer to this is O-atom.

Explanation: The Bronsted acid-base theory is the backbone of chemistry. This theory focuses mainly on acids and bases acting as proton donors or proton acceptors.

A^+ + B^- \rightarrow A-B

where A^+ is the Lewis Acid and B^- is the Lewis Base and A-B is the Covalent Bond.

Reaction of dissociation of HNO2 in H_2O is given as:

HNO_2 + H_2O \rightarrow H_3O^+ + NO_2^-

In this reaction O-atom has lone pair in water and therefore it accepts the proton from HNO_2 forming a Lewis Base.

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Which of the following pictures correctly show the structure of the H+ ion? Click on the picture to see each choice.
lutik1710 [3]

Answer: It's only one proton in the middle of the red circle there's nothing outside it.

Explanation: I'm not sure sorry :|

hope this helps

7 0
3 years ago
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an electric current causes water to be transformed into hydrogen and oxygen gasses a physical change or a chemical change
Natalija [7]
Physical change because ther is force which is the electric current
3 0
3 years ago
2CH3CHO+O2=> 2CH3COOH
Dovator [93]

Answer:

2CH3CHO + O2 → 2CH3COOH

7 0
2 years ago
A sample of gaseous neon atoms at atmospheric pressure and 0 °c contains 2.69 * 1022 atoms per liter. the atomic radius of neon
omeli [17]

Explanation

Radius of neon atom : 69 pm = 69\times 10^{-12} m

Volume occupied by the one atom:\frac{4}{3}\pi r^3

=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3

given that 2.69\times 10^{22} atoms are present in 1L

1 L = 0.001 m^3

The volume occupied by the 2.69\times 10^{22} neon atoms

2.69\times 10^{22}\times 1.37\times 10^{-30} m^3=3.68\times 10^{-8} m^3

Fraction of volume occupied by the neon atom:

=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3

3.68\times 10^{-11} m^3

The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

3 0
3 years ago
How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this pro
dexar [7]

n = PV/RT

p = 1.6 atm

v = 12.7L

R = 0.0821

T = 24°C which is equivalent to 297.15 degrees k

n = (16 × 12.7) / (0.0821 × 297.15)

n = 20.32 / 24.39

n = 0.83 mol

C = 12.90

H = 1.0079

C2 = 12.010 × 2 = 24.02

H6 = 1.0079 × 6 = 6.0474

C2H6 = 30.0674

Ethane times n which is 30.0674 × 0.83mol

= 24.95 grams of C2H6. Which is Ethane.

4 0
4 years ago
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