1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr402 [8]
3 years ago
8

When hno2 dissociates in water, which atom is dontaing electrons, allowing water to act as a lewis base?

Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0

Answer to this is O-atom.

Explanation: The Bronsted acid-base theory is the backbone of chemistry. This theory focuses mainly on acids and bases acting as proton donors or proton acceptors.

A^+ + B^- \rightarrow A-B

where A^+ is the Lewis Acid and B^- is the Lewis Base and A-B is the Covalent Bond.

Reaction of dissociation of HNO2 in H_2O is given as:

HNO_2 + H_2O \rightarrow H_3O^+ + NO_2^-

In this reaction O-atom has lone pair in water and therefore it accepts the proton from HNO_2 forming a Lewis Base.

You might be interested in
The anticodon is the three-base code on the tRNA molecule that binds to the codon on mRNA. What is the associated codon for the
neonofarm [45]
It is AAU
A-U
U-A
C-G
G-C
5 0
3 years ago
Read 2 more answers
You need to make an aqueous solution of 0.182 M aluminum sulfate for an experiment in lab, using a 250 mL volumetric flask. How
Ksju [112]

Answer:

Hence, 15.99 g of solid Aluminum Sulfate should be added in 250 mL of Volumetric flask.

Explanation:

To make 0.187 M of Aluminum Sulfate solution in a 250 mL (0.250 L) Volumetric flask  

The molar mass of Aluminum Sulfate = 342.15 g/mol  

Using the molarity formula:-  

Molarity = Number of moles/Volume of solution in a liter  

Number of moles = Given weight/ molar mass  

Molarity = (Given weight/ molar mass)/Volume of solution in liter  

0.187 M = (Given weight/342.15 g/mol)/0.250 L  

Given weight = 15.99 g  

8 0
3 years ago
I’m very confused on how to solve this
Bond [772]
Recall that density is Mass/Volume. We are given the mL of liquid which is volume so all we need is mass now. We are given the mass of the granulated cylinder both with and without the liquid, so if we subtract them, we can get the mass of the liquid by itself. So, 136.08-105.56= 30.52g. This is the mass of the liquid. We now have all we need to find the density. So, let’s plug these into the density formula. 30.52g/45.4mL= 0.672 g/mL. This is our final answer since the problem requests the answer in g/mL, but be careful, because some problems in the future may ask for g/L requiring unit conversions. Also note that 30.52 was 4 sigfigs and 45.4 was 3 sigfigs, and so dividing them required an answer that was 3 sigfigs as well, hence why the answer is in the thousandths place
4 0
3 years ago
14. Which graph (below) accurately illustrates the motion of description A:
sertanlavr [38]
I can’t see the picture it’s blank take another willing to help
8 0
3 years ago
Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
Other questions:
  • PLZ I NEED THIS NOW A chemical change can also be called a chemical _________.
    14·2 answers
  • A marathon is a race that commemorates the run made by a Greek soldier, Pheidippides, that took place in August 490 BC. The sold
    14·2 answers
  • What is the maximum number of electrons in the following energy level?
    13·1 answer
  • 75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new so
    12·1 answer
  • There are over 100 elements, but only
    14·1 answer
  • Giving brainliest please help with this question
    8·1 answer
  • How many digits to the right of the decimal point should be used to report the result?
    6·1 answer
  • Which of the following is NOT a type of mucle tissue?
    11·2 answers
  • Why does 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC? (Hint - the heat c
    9·1 answer
  • NEED HELP! SCIENCE HW IS DUE IN 1 HOUR!!!!!!!!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!