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Novosadov [1.4K]
3 years ago
9

A random sample of 30 receipts for individuals shopping at the Community DrugStore showed the sample mean to be x-bar = $28.19 w

ith a sample standard deviation of s = $4.06. Compute the coefficient of variation for this data.
a. 6.94%
b. 14.4% Correct
c. 694%
d. 4.32%
Mathematics
2 answers:
Triss [41]3 years ago
7 0
Yes the answer to this question is B.
Margarita [4]3 years ago
6 0
14.4 is correct witch ur answer is B
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The hourly median power (in decibels) of received radio signals transmitted between two cities
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Using the lognormal and the binomial distributions, it is found that:

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In a <em>lognormal </em>distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{\ln{X} - \mu}{\sigma}

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In this problem:

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The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>

Z = \frac{\ln{X} - \mu}{\sigma}

1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}

\ln{X} - 3.5 = 1.28\sqrt{1.22}

\ln{X} = 1.28\sqrt{1.22} + 3.5

e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}

X = 136

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the <u>p-value of Z when X = 150</u>, hence:

Z = \frac{\ln{X} - \mu}{\sigma}

Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}

Z = 1.37

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Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • p is the probability of a success on a single trial.

For this problem, we have that p = 0.9147, n = 10, and we want to find P(X = 6), then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065

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You can learn more about the binomial distribution at brainly.com/question/24863377

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