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stiv31 [10]
3 years ago
11

Why are the values for sine and cosine equal at 45°?

Mathematics
2 answers:
cestrela7 [59]3 years ago
8 0
For this case we have a rectangle triangle.
 The opposite leg is the sine of the angle.
 The adjacent catheto is the cosine of the angle.
 For 45 degrees, the length of both legs is the same.
 Thus,
 Sine (45) = Cosine (45)
 Answer:
 
The length of the legs is the same for a 45 degree angle.
Natasha_Volkova [10]3 years ago
3 0

Answer:

The complement of 45\degree is 45\degree.

Step-by-step explanation:

<u>Method 1</u>

From the isosceles right triangle; See diagram in attachment.

\sin(45\degree)=\frac{x}{x\sqrt{2} }


\sin(45\degree)=\frac{1}{\sqrt{2} }


\sin(45\degree)=\frac{\sqrt{2}}{2 }


Also;


\sin(45\degree)=\frac{x}{x\sqrt{2} }


\cos(45\degree)=\frac{1}{\sqrt{2} }


\cos(45\degree)=\frac{\sqrt{2}}{2 }

Hence;

\cos(45\degree)=\sin(45\degree)


<u>Method 2</u>

\sin(45\degree)=\cos(45\degree) because the complement of 45\degree is still 45\degree.


Complementary angles add to 90\degree.

In general if we have an angle \theta, then its complement is (90-\theta)\degree.

There is a relationship between the sine of an angle,\theta and the cosine of its complement,(90-\theta)\degree[/tex].


The relationship is that,

\sin(\theta \degree)=\cos((90-\theta)\degree).


If \theta=45\degree, then


\sin(45 \degree)=\cos((90-45)\degree).


\Rightarrow \sin(45\degree)=\cos(45\degree).


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Consider two forces of 17 and 42 pounds both acting in the horizontal direction on a single object. find the resultant force act
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The forces have a magnitude of 59 pounds, and their direction angles are zero.

<h3>What is the magnitude of force?</h3>
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Two forces of 17 and 42 pounds act horizontally on an object.

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To learn more about the Magnitude of forces and Direction angles of forces, refer to:

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