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xxMikexx [17]
4 years ago
5

You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont

al range. You shoot the gun straight up, and it takes 4.4 ss for the dart to land back at the barrel.What is the maximum horizontal range of your gun (in meters)?
Physics
1 answer:
Rashid [163]4 years ago
6 0

Answer:

47.48 m

Explanation:

The horizontal range of an object can be estimated using the equation below:

S_{x} =\frac{v^{2}*sin (2\alpha)}{g}

For the maximum horizontal range to occur, the angle \alpha is 45°. Then, the horizontal range will be:

S_{x} = \frac{v^{2}*sin 90}{g} = \frac{v^{2}}{g}

In addition, the velocity (v) can be estimated using the equation below:

v = gt/2

Therefore, the maximum horizontal range is:

S_{x} =  \frac{(gt/2)^{2}}{g} = (9.81*4.4/2)^2 / 9.81 = 47.48 m

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Answer:

f.The period is independent of the suspended mass.

Explanation:

The period of a pendulum is given by

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From the formula, we see that:

1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length

2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation

So, the only correct statements are

f.The period is independent of the suspended mass.

Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

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3 years ago
If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step
azamat

Answer:

Explanation:

v_f^2 = v_i^2-2a(x_f-x_i)

Subtract both sides by v_i^2:

- v_i^2+v_f^2 = -2a(x_f-x_i)

Divide both sides by -2*a:

\frac{v_i^2 - v_f^2}{2a} =x_f-x_i

Add both sides by x_i:

x_i+\frac{v_i^2 - v_f^2}{2a} =x_f

Subtract both sides by \frac{v_i^2 - v_f^2}{2a}:

x_i=x_f-\frac{v_i^2 - v_f^2}{2a}

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A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
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