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3 years ago

How does the current model of the atom differ from j j thomas model

Physics

1 answer:

bixtya [17]3 years ago

4 0

Jj thomas' model contained electrons.

The current model contains a nucleus with electrons orbiting around it. :)

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Calculate the force exerted by a mental ball having a mass of 70kg moving with speed of 20m/s>2

lord [1]

Answer:

F = 1400 N

Explanation:

It is given that,

Mass of the ball, m = 70 kg

It is moving with an acceleration of 20 m/s². We need to find the force exerted by the ball.

Force is given by the product of mass and acceleration. So,

F = ma

$F=70\ kg\times \ 20m/s^2\\\\F=1400\ N$

So, the force of 1400 N is exerted by a metal ball.

8 0

3 years ago

Why is a minimum of three seismic stations needed to find the epicenter of an earthquake?

vazorg [7]

Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.

5 0

3 years ago

What is the magnitude of the torque about his shoulder due to the weight of the ball and his arm if he holds his arm straight ou

Lubov Fominskaja [6]

Answer:

The torque about his shoulder is 34.3Nm.

The solution approach assumes that the weight of the boy's arm acts at the center of the boy's arm length 35cm from the shoulder.

Explanation:

The solution to the problem can be found in the attachment below.

6 0

3 years ago

An iron cube has edge 15cm long at 20c .What will be? The new surface area of a face when the temperature rises to 80c

grigory [225]

Answer:

271cm^2

Explanation:

volume 1= 15^3 =3375

temp. 1. = 20+273 = 293

temp. 2. = 50+273 = 353

volume 2 =?

According to Charles law

volume is proportional to temperature

v2 = v1 * t2 / t1

v2 = 3375 * 353 / 293

v2 = 4066cm^3

v = area * length

4066 = area * 15

area = 4066/15 = 271cm^2

3 0

3 years ago

An atom of carbon has a radius of 67.0 pm and the average orbital speed of the electrons in it is about 1.3 x 10⁶ m/s.

adoni [48]

Answer :

The least possible uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

The percentage of the average speed is, 33 %

Explanation :

According to the Heisenberg's uncertainty principle,

$\Delta x\times \Delta p=\frac{h}{4\pi}$ ...........(1)

where,

$\Delta x$ = uncertainty in position

$\Delta p$ = uncertainty in momentum

h = Planck's constant

And as we know that the momentum is the product of mass and velocity of an object.

$p=m\times v$

or,

$\Delta p=m\times \Delta v$ .......(2)

Equating 1 and 2, we get:

$\Delta x\times m\times \Delta v=\frac{h}{4\pi}$

$\Delta v=\frac{h}{4\pi \Delta x\times m}$

Given:

m = mass of electron = $9.11\times 10^{-31}kg$

h = Planck's constant = $6.626\times 10^{-34}Js$

radius of atom = $67.0pm=67.0\times 10^{-12}m$ $(1pm=10^{-12}m)$

$\Delta x$ = diameter of atom = $2\times 67.0\times 10^{-12}m=134.0\times 10^{-12}m$

Now put all the given values in the above formula, we get:

$\Delta v=\frac{6.626\times 10^{-34}Js}{4\times 3.14\times (134.0\times 10^{-12}m)\times (9.11\times 10^{-31}kg)}$

$\Delta v=4.32\times 10^{5}m/s$

The minimum uncertainty in an electron's velocity is, $4.32\times 10^{5}m/s$

Now we have to calculate the percentage of the average speed.

Percentage of average speed = $\frac{\text{Uncertainty in speed}}{\text{Average speed}}\times 100$

Uncertainty in speed = $4.32\times 10^{5}m/s$

Average speed = $1.3\times 10^{6}m/s$

Percentage of average speed = $\frac{4.32\times 10^{5}m/s}{1.3\times 10^{6}m/s}\times 100$

Percentage of average speed = 33.2 % ≈ 33 %

Thus, the percentage of the average speed is, 33 %

3 0

3 years ago